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Ta có : 2003/2005 +2/2005=2003/2005+6/6015=1
2128/2134+6/2134=1
Vì 6/6015<6/2134 nên 2003/2005<2128/2134
Vậy 2003/2005<2128/2134
Ta có :2003/2005+2/2005=2003/2005+6/6015=1
2128/2134+6/2034=1
Vì 6/6015<6/2034 nên 2003/2005>2128/2134
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\(1-\frac{37}{39}=\frac{2}{39}\)
\(1-\frac{2015}{2017}=\frac{2}{2017}\)
\(\frac{2}{39}>\frac{2}{2017}\Leftrightarrow\frac{37}{39}< \frac{2015}{2017}\)
1 - 37 / 39 = 2 / 39
1 - 2015 / 2017 = 2 / 2017
2 / 39 > 2 / 2017
Nên 37 / 39 < 2015 / 2017
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\(\frac{2006}{2007}< \frac{2007}{2008}\)
\(\frac{39}{16}>\frac{15}{40}\)
\(\frac{37}{67}< \frac{377}{677}\)
\(\frac{22}{67}< \frac{51}{512}\)
\(\frac{22}{67}< \frac{51}{512}\)
Ủng hộ mk nha
![](https://rs.olm.vn/images/avt/0.png?1311)
2003/2005=0,999
2128/2134=0,997
vậy 2003/2005 > 2128/2134
31/90>30/90=1/3=17/51>16/51
=>31/90>16/51
làm nhanh gọn nhẹ !
Ta có:16/51<17/51=1/3=30/90<31/90
=> 16/51<1/3<31/90
Vậy 16/51<31/90