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a) Phân số trung gian: 24/59
15/59 < 24/49 < 24/97.
=> 15/59 < 24/97.
b) Phân số trung gian: 19/47.
12/47 < 19/47 < 19/77.
=> 12/47 < 19/77.
@Cỏ
#Forever
a, Phân số trung gian: 15/97
15/59<15/57, 24/97>15/97
=> 15/59<15/57<24/97
=> 15/59<24/97
b, Ps trung gian là: 12/77
12/47>12/77
19/77>12/77
12/47>12/77<19/77
=> 12/47<19/77
~ HT ~
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(1-\frac{1998}{1999}=\frac{1}{1999}\)
\(1-\frac{1999}{2000}=\frac{1}{2000}\)
Vì \(\frac{1}{1999}>\frac{1}{2000}\)nên \(\frac{1998}{1999}< \frac{1999}{2000}\)
b) Ta có :
\(\frac{1999}{2001}< 1\)
\(\frac{12}{11}>1\)
Nên \(\frac{1999}{2001}< \frac{12}{11}\)
c)
\(1-\frac{13}{27}=\frac{14}{27}\)
\(1-\frac{27}{41}=\frac{14}{41}\)
Vì \(\frac{14}{27}>\frac{14}{41}\)nên \(\frac{13}{27}< \frac{27}{41}\)
d)
Ta có phân số trung gian là \(\frac{23}{45}\).
Ta có : \(\frac{23}{47}< \frac{23}{45}\) ; \(\frac{24}{45}>\frac{23}{45}\)
Nên \(\frac{23}{47}< \frac{24}{45}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có : a + 1 > a - 1
=> \(\frac{1}{a+1}\) < \(\frac{1}{a-1}\)
a) \(\frac{1}{a+1}< \frac{1}{a}< \frac{1}{a-1}\Rightarrow\frac{1}{a+1}< \frac{1}{a-1}\)
b) \(\frac{23}{47}< \frac{23}{45}< \frac{24}{45}\Rightarrow\frac{23}{47}< \frac{24}{45}\)
c) \(\frac{12}{17}>\frac{1}{2}>\frac{7}{15}\Rightarrow\frac{12}{17}>\frac{7}{15}\)
d) \(\frac{34}{43}< \frac{35}{43}< \frac{35}{42}\Rightarrow\frac{34}{43}< \frac{35}{42}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{15}{59}>\dfrac{15}{60}=\dfrac{1}{4}\)
\(\dfrac{24}{97}< \dfrac{24}{96}=\dfrac{1}{4}\)
\(\Rightarrow\dfrac{15}{59}>\dfrac{24}{97}\)
b) \(\dfrac{12}{47}>\dfrac{12}{48}=\dfrac{1}{4}\)
\(\dfrac{19}{77}< \dfrac{19}{76}=\dfrac{1}{4}\)
\(\Rightarrow\dfrac{12}{47}>\dfrac{19}{77}\)
a: \(\dfrac{15}{59}>\dfrac{15}{60}=\dfrac{1}{4}\)
\(\dfrac{1}{4}=\dfrac{24}{96}>\dfrac{24}{97}\)
Do đó: \(\dfrac{15}{59}>\dfrac{24}{97}\)