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so sánh
1.-16/121 và -24/113
2.49/56,47/58 và 49/58
3.27/73 và 271/731
4.31/7 và 35/8
5.-47/48 và -68/69
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{27}{73}< \frac{271}{73}\)
Mà: \(\frac{271}{73}>\frac{271}{731}\)
Nên \(\frac{27}{73}< \frac{271}{731}\)
Ta có: 27/73 = 270/730
Áp dụng a/b < 1 => a/b < a+m/b+m (ab,m thuộc N*)
=> 270/730 < 270+1/730+1
=> 27/73 < 271/731
Ủng hộ mk nha ^_-
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776 - { 5. [ 409 - (8.3 - 212)] - 1724}
= 776 - { 5.[ 409 - (24 - 441)] - 1724}
= 776 - { 5.[ 409 + 417] - 1724}
= 776 - {5. 826 - 1724}
= 776 - 2406
= - 1630
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\(476-\left\{5.\left[409-\left(8.3-21^2\right)\right]-1724\right\}\)
\(=476-\left\{5.\left[409-\left(24-21\right)^2\right]-1724\right\}\)
\(=476-\left\{5.\left[409-3^2\right]-1724\right\}\)
\(=476-\left\{5.\left[409-9\right]-1724\right\}\)
\(=476-\left\{5.400-1724\right\}\)
\(=476-\left\{2000-1724\right\}\)
\(=476-276=200\)
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`@` `\text {Ans}`
`\downarrow`
`3^4*5^2 - 128*2^3 + 1^17`
`= 9^2*5^2 - 2^7*2^3 + 1`
`= (9*5)^2 - 2^10+1`
`= 45^5-2^10 + 1`
`= 2025 - 1024 + 1`
`= 2025 - 1023`
`= 1002`
\(24-4^2\div4\cdot2+3\)
`= 24 - 4*2 + 3`
`= 24 - 8 + 3`
`= 24 - 5`
`= 19`
`@` `\text {Kaizuu lv u}.`
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D = 500 - {5.[409 - (23 . 3 + 21)2] - 1724}
D = 500 - {5.[409 - (8 . 3 + 21)2] - 1724}
D = 500 - {5.[409 - (24 + 21)2] - 1724}
D = 500 - {5.[409 - 452] - 1724}
D = 500 - {5.[409 - 2025] - 1724}
D = 500 - {5.(-1616) - 1724}
D = 500 - {-8080 - 1724}
D = 500 - (-9804)
D = 500 + 9804
D = 10304
D=500-\(\left\{5\cdot[409-\left(2^3\cdot3+21\right)^2-1724\right\}\)=500-\(\left\{5\cdot[409-45^2-1724]\right\}\)
=500-\(\left\{5\cdot[409-2025-1724]\right\}\)=500-\(\left\{5\cdot\left(-3340\right)\right\}\)=500+16700=17200.
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 1 5 + 2 9 + 4 5 + − 11 9 + 3 7 = 1 5 + 4 5 + 2 9 + − 11 9 + 3 7 = 1 + ( − 1 ) + 3 7 = 3 7
b) − 7 31 + 24 17 + 7 31 + − 5 17 + 1 = − 7 31 + 7 31 + 24 17 + − 5 17 + 1 = 0 + 19 17 + 1 = 36 17
7^31>17^24