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a. \(\frac{26}{42}< \frac{56}{78}\)
b.\(\frac{58}{89}< \frac{36}{53}\)
c.\(\frac{1530}{1632}>\frac{1414}{1515}\)
d.\(\frac{-373737}{515151}>\frac{-1111}{1212}\)
k cho mk nha!!!!
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71–(–30)–37 – 81 + 37
=71+30-37-81+37
=(71+30)+(-37+37)-81
=101+0-81
=20
(–56) + 26 + 14 + 56
=(-56+56)+(26+14)
=0+40
=40
1632 –37– (– 157) – 163 – 1532
=(1632-1532)+(-37+157)-163
=1100+120-163
=1220-163
=1057
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a: \(7\cdot\left(-2\right)^3-12\cdot\left(-5\right)+\left(-17\right)\)
\(=7\cdot\left(-8\right)+60-17\)
=-56+43
=-13
b: \(1632-37-\left(-157\right)-163-1532\)
\(=\left(1632-1532\right)-37-163+157\)
=100-200+157
=57
c: \(47\cdot\left(-918\right)+\left(-53\right)\cdot918\)
\(=918\left(-47\right)+\left(-53\right)\cdot918\)
\(=918\cdot\left(-47-53\right)\)
\(=918\left(-100\right)=-91800\)
d: \(\left(-52\right)\cdot\left(-281\right)+\left(-52\right)\cdot181\)
\(=\left(-52\right)\left(-281+181\right)\)
\(=\left(-52\right)\cdot\left(-100\right)=5200\)
a: 7⋅(−2)3−12⋅(−5)+(−17)7⋅(−2)3−12⋅(−5)+(−17)
=7⋅(−8)+60−17=7⋅(−8)+60−17
=-56+43
=-13
b: 1632−37−(−157)−163−15321632−37−(−157)−163−1532
=(1632−1532)−37−163+157=(1632−1532)−37−163+157
=100-200+157
=57
c: 47⋅(−918)+(−53)⋅91847⋅(−918)+(−53)⋅918
=918(−47)+(−53)⋅918=918(−47)+(−53)⋅918
=918⋅(−47−53)=918⋅(−47−53)
=918(−100)=−91800=918(−100)=−91800
d: (−52)⋅(−281)+(−52)⋅181(−52)⋅(−281)+(−52)⋅181
=(−52)(−281+181)=(−52)(−281+181)
=(−52)⋅(−100)=5200=(−52)⋅(−100)=5200
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a: 43/52>26/52=1/2=60/120
b: 17/68=1/4<1/3=35/105<35/103
c: \(\dfrac{2018\cdot2019-1}{2018\cdot2019}=1-\dfrac{1}{2018\cdot2019}\)
\(\dfrac{2019\cdot2020-1}{2019\cdot2020}=1-\dfrac{1}{2019\cdot2020}\)
2018*2019<2019*2020
=>-1/2018*2019<-1/2019*2020
=>\(\dfrac{2018\cdot2019-1}{2018\cdot2019}< \dfrac{2019\cdot2020-1}{2019\cdot2020}\)
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Bai 2 :
\(\hept{\begin{cases}x+y=7\\x-7=13\end{cases}\Leftrightarrow\hept{\begin{cases}x+y=7\\x=20\end{cases}}}\)
Thay x vào phương trình đầu ta có :
\(20+y=7\Leftrightarrow y=-13\)
Vậy \(\left\{x;y\right\}=\left\{20;-13\right\}\)
Thử \(20-13=7\); \(20-7=13\)( thỏa mãn )
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\(\dfrac{19}{19}\) = 1 < \(\dfrac{2005}{2004}\) vậy \(\dfrac{19}{19}\) < \(\dfrac{2005}{2004}\)
\(\dfrac{72}{73}\) = 1 - \(\dfrac{1}{73}\)
\(\dfrac{98}{99}\) = 1 - \(\dfrac{1}{99}\)
Vì \(\dfrac{1}{73}\) > \(\dfrac{1}{99}\) nên \(\dfrac{72}{73}\) < \(\dfrac{98}{99}\)
ta có : \(64^{27}=\left(2^6\right)^{27}=2^{162}\),\(16^{32}=\left(2^4\right)^{32}=2^{128}\).do 162>128 nên \(64^{27}>16^{32}\)
6427> 1632
Không cần nhìn ta biết là 6427> 1632
tk nhé