Question

[Nguyễn Hương Giang]

So sánh 2 số:

a) A= (2+1)(2^2+1)(2^4+1)(2^16) và B= 2^32-1

Answer 1

[Hoàng Lê Bảo Ngọc]

Ta có : 

\(A=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^{16}+1\right)\)

\(=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^{16}+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^{16}+1\right)\)

= ..................................................................

\(=\left(2^{16}-1\right)\left(2^{16}+1\right)=2^{32}-1=B\)

=> A = B

Answer 2

[Trần Việt Linh]

Đề thiếu