Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{14xy^5\left(2x-3y\right)}{21x^2y\left(2x-3y\right)^2}=\frac{2y^4}{3x\left(2x-3y\right)}\)
1/ x3 + x2y - x2z -xyz
= x2(x + y) - xz(x + y)
= (x + y) (x2 - xz)
= x (x + y) (x - z)
2/ 3x3y - 18x2y2 + 27xy3
= 3xy(x2 - 6xy + y2)
\(=\frac{2.7.xy.y^5\left(2x-3y\right)}{3.7.xy.x\left(2x-3y\right)^2}=\frac{2y^5}{3x\left(2x-3y\right)}\)
\(\frac{14xy^5\left(2x-3y\right)}{21x^2y\left(2x-3y\right)^2}\)
\(=\frac{2y^4}{3x\left(2x-3y\right)}\)
A=(8xy-6x^2)/(12y^2-9xy)
A=2x(4y-3x)/3y(4y-3x)
A=2x/3y
B=(2x^3-18x)/(x^4-81)
B=2x(x^2-9)/(x^2-9)(x^2+9)
B=2x/(x^2+9)
C=(x^2-x-30)/(x^2-25)
C=(x^2+6x-5x-30)/(x^2-25)
C=(x(x+6)-5(x+6))/(x-5)(x+5)
C=(x+6)(x-5)/(x-5)(x+5)
C=(x+6)/(x+5)
\(\frac{2x^4+6x^3+18x^2}{x^4-27x}=\frac{2x^2.\left(x^2+3x+9\right)}{x.\left(x^3-27\right)}\)
\(=\frac{2x^2.\left(x^2+3x+9\right)}{x.\left(x-3\right)\left(x^2+3x+9\right)}=\frac{2x}{x-3}\)
Câu 1:
a) 2x(3x+2) - 3x(2x+3) = 6x^2+4x - 6x^2-9x = -5x
b) \(\left(x+2\right)^3+\left(x-3\right)^2-x^2\left(x+5\right)\)
\(=x^3+6x^2+12x+8+x^2-6x+9-x^3-5x^2\)
\(=2x^2+6x+17\)
c) \(\left(3x^3-4x^2+6x\right)\div\left(3x\right)=x^2-\dfrac{4}{3}x+2\)
2x2/3x3