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\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\frac{\left(-5\right)^3.40.4^3}{5.27.4^7}=\frac{\left(-5\right)^3.2}{3^3.4^3}=\frac{\left(-5\right)^3}{3^3.2^5}\)
có gì sai bỏ qua
\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{3^{10}.\left(-5\right)^{20}.\left(-5\right)}{\left(-5\right)^{20}.3^{10}.3^2}=\frac{-5}{3^2}=-\frac{5}{9}\)
1 Rút gọn phân số
a)\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
= \(\frac{\left(-125\right).40.64}{135.16384.1}\)
= \(\frac{\left(-5000\right).64}{2211840}\)
= \(\frac{-320000}{2211840}\)
= \(\frac{-125}{864}\)
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\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.1}=\dfrac{\left(-15\right).40.64}{135.\left(-2\right)^{14}}=\dfrac{\left(-5\right).3.5.8.64}{15.9.\left(-2\right)^{14}}=\dfrac{8.\left(-5\right).\left(-2\right)^6}{9.\left(-2\right)^{14}}=\dfrac{\left(-2\right)^3.5}{9.\left(-2\right)^8}=\dfrac{5}{9.\left(-2\right)^5}\)
\(a,\dfrac{2929-101}{2.1919+404}=\dfrac{29.101-101.1}{2.19.101+4.101}\)
\(=\dfrac{101\left(29-1\right)}{101\left(2.19+4\right)}\)
\(=\dfrac{101.29}{101.42}\)
\(=\dfrac{28}{42}=\dfrac{2}{3}\)
\(b,\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}}\)
\(=\dfrac{40.\left(-15\right).64}{135.\left(-2\right)^{14}}\)
\(=\dfrac{5.8.3.\left(-5\right).64}{5.3.9.\left(-2\right)^{14}}\)
\(=\dfrac{8.\left(-5\right).\left(-2\right)^6}{9.\left(-2\right)^{14}}\)
\(=\dfrac{\left(-2\right)^3.5}{9.\left(-2\right)^8}=\dfrac{5}{9.\left(-2\right)^5}\)
\(\frac{-5^3\cdot40\cdot4^3}{135\cdot\left(-2\right)^{14}\left(-100\right)^0}=\frac{-125\cdot2^3\cdot5\cdot\left(2^2\right)^3}{5\cdot27\cdot2^{14}\cdot1}=\frac{-125\cdot2^6}{27\cdot2^{11}}=\frac{-125}{27\cdot2^5}=\frac{-125}{864}\)
\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)\(=\frac{\left(-5\right)^3.5.2^3.2^6}{3^3.5.2^{14}.1}\)\(=\frac{-125}{864}\)