Question

[Thiên Bình Đáng Yêu]

Rút gọn A

\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+.....+\frac{1}{2^{50}}\)

Answer 1

[»βέ•Ҫɦαηɦ«]

Ta có : \(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+......+\frac{1}{2^{50}}\)

\(\Rightarrow2A=1+\frac{1}{2}+\frac{1}{2^2}+.....+\frac{1}{2^{49}}\)

\(\Rightarrow2A-A=1-\frac{1}{2^{50}}\)

\(\Rightarrow A=1-\frac{1}{2^{50}}\)

Answer 2

[Trương Nhật Linh]

   \(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{50}}\)

  \(2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{49}}\)

\(2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{49}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{50}}\right)\)

              \(A=1-\frac{1}{2^{50}}\)

               \(A=\frac{2^{50}-1}{2^{50}}.\)