![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x 2 – 2xy + y 2 - z 2
= ( x 2 – 2xy + y 2 ) – z 2
= x - y 2 – z 2
= (x – y + z)(x – y – z)
![](https://rs.olm.vn/images/avt/0.png?1311)
x 2 y + x y 2 + x 2 z + x z 2 + y 2 z + y z 2 + 3xyz.
= ( x 2 y + x 2 z + xyz) + (x y 2 + y 2 z + xyz) + (x z 2 + y z 2 + xyz)
= x(xy + xz + yz) + y(xy + yz + xz) + z(xz + yz + xy)
= (x + y + z)(xy + xz + yz).
\(x^2y+xy^2+x^2z+xz^2+y^2z+yz^2+3xyz\)
\(=\left(x^2y+x^2z+xyz\right)+\left(xz^2+yz^2+xyz\right)+\left(xy^2+y^2z+xyz\right)\)
\(=x\left(xy+xz+yz\right)+z\left(xz+yz+xy\right)+y\left(xy+yz+xz\right)\)
\(=\left(x+y+z\right)\left(xy+yz+xz\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\left(x^2-2x+1\right)-\left(y^2-2yz+z^2\right)\)
\(=\left(x-1\right)^2-\left(y-z\right)^2\)
\(=\left(x-1-y+z\right)\left(x-1+y-z\right)\)
\(x^2-2x+1-y^2+2yz-z^2\)
\(=\left(x-1\right)^2-\left(y-z\right)^2\)
\(=\left(x-1-y+z\right)\left(x-1+y-z\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x2 – 2xy + y2 – z2 + 2zt – t2
(Nhận thấy x2 – 2xy + y2 và z2 – 2zt + t2 là các hằng đẳng thức)
= (x2 – 2xy + y2) – (z2 – 2zt + t2)
= (x – y)2 – (z – t)2 (xuất hiện hằng đẳng thức (3))
= [(x – y) – (z – t)][(x – y) + (z – t)]
= (x – y – z + t)(x – y + z –t)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: Ta có: \(x^2-xy-3x+3y\)
\(=x\left(x-y\right)-3\left(x-y\right)\)
\(=\left(x-y\right)\left(x-3\right)\)
b: Ta có: \(5x^2+5xy-x-y\)
\(=5x\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(5x-1\right)\)
c: Ta có: \(x^2-2xy+y^2-z^2\)
\(=\left(x-y\right)^2-z^2\)
\(=\left(x-y-z\right)\left(x-y+z\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b: \(x^2-2xy+y^2-z^2\)
\(=\left(x-y\right)^2-z^2\)
\(=\left(x-y-z\right)\left(x-y+z\right)\)
d: \(x^2+4x+3=\left(x+3\right)\left(x+1\right)\)
TL :
x2-x-y2-y=(x2-y2)-(x+y)=(x-y)(x+y)-(x+y)=(x+y)(x-y-1)
x2-xy+x-y=x(x-y)+(x-y)=(x+1)(x-y)