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a, ( 2600 + 6400 ) - 3.x = 1200
9000 - 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 2600
b, [ ( 6.x - 72 ) : 2 - 84 ] .28 = 5628
( 6.x - 72 ) : 2 - 84 = 5628 : 28
( 6.x - 72 ) : 2 - 84 = 201
( 6.x - 72 ) : 2 = 201 + 84
( 6.x - 72 ) : 2 = 285
6.x - 72 = 208 x 2
6.x - 72 = 416
6.x = 416 + 72
6.x = 488
x = 244/3
a)(2600 + 6400) - 3.x = 1200
9000 -3.x = 1200
3.x =9000-1200
3.x=7800
x=7800:3
=2600
nói chung bài bn CÔNG CHÚA XINH XẮN ĐÚNG RỒI
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(2600+6400)-3.x=1200
=>9000-3.x=1200
=>3.x=9000-1200
=>3.x=7800
=>x=7800:3
=>x=2600
![](https://rs.olm.vn/images/avt/0.png?1311)
( 2600+6400 ) - 3. x = 1200
9000 -3 . x = 1200
3 . x = 9000-1200
3 . x = 7800
x = 7800 : 3
x = 2600
![](https://rs.olm.vn/images/avt/0.png?1311)
(2600 + 6400) – 3x = 1200
9000 – 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 7800 : 3
x = 2600
Vậy x = 2600
![](https://rs.olm.vn/images/avt/0.png?1311)
a,(2600+6400)-3 .x = 1200
=> 9000-3 .x= 1200
=> 3.x= 7800
=. x=2600
b, (6.x-72):2-84= 201
(6x-72):2=285
6x-72=570
6x=642
x=107
a) ( 2600 + 6400 ) - 3 . x = 1200
9000 - 3 . x = 1200
3 . x = 9000 - 1200
3 . x = 7800
x = 7800 : 3
x = 2600
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(2600+6400\right)-3-x=1200\)
\(\Rightarrow9000-3-x=1200\)
\(\Rightarrow3-x=9000-1200\)
\(\Rightarrow3-x=7800\)
\(\Rightarrow x=7797\)
b) \(\left[\left(6\cdot x-72\right):2-84\right]\cdot28=5628\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=5628:28\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=201\)
\(\Rightarrow\left(6\cdot x-72\right):2=201+84\)
\(\Rightarrow\left(6\cdot x-72\right):2=285\)
Đến dei bạn tự làm, ý b mình không chắc chắn lắm
![](https://rs.olm.vn/images/avt/0.png?1311)
#)Giải :
\(123-5\left(x+4\right)=38\)
\(\Leftrightarrow5\left(x+4\right)=85\)
\(\Leftrightarrow x+4=17\)
\(\Leftrightarrow x=13\)
\(\left(3x-16\right)343=2.2401\)
\(\Leftrightarrow\left(3x-16\right)343=4802\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=10\)
\(\left(2600+6400\right)-3x=1200\)
\(\Leftrightarrow9000-3x=1200\)
\(\Leftrightarrow3x=7800\)
\(\Leftrightarrow x=2600\)
P/s : Câu cuối cùng lỗi chỗ b4 ph k ? hay là tìm cả b và x thế ???
\(123-5\left(x+4\right)=38\)
\(=>123-5x-20=38\)
\(=>-5x=-123+20+38\)
\(=>-5x=-65\)
\(=>x=13\)
b, \(\left(3x-16\right)343=2.2401\)
=>1029x -5488= 4802
=> 1029x=5488+4802
=> 1029x= 10290
=> x=10
c, (2600+6400)-3x=1200
=> 9000-3x=1200
=> -3x= -9000+1200
=> -3x= -7800
=> x=2600
d,
k hiểu đề
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (2600 + 6400) - 3 . x = 1200
9000 - 3.x = 1200
3x = 9000-1200
3x = 7800
x = 7800:3
x = 2600
b) câu này ko có tổng hả Công chúa nhí nhảnh? check lại giùm Nhi nha!
a) \(\left(2600+6400\right)-3x=1200\)
\(9000-3x=1200\)
\(3x=9000-1200\)
\(3x=7800\)
\(x=\frac{7800}{3}\)
\(x=2600\)
vậy \(x=2600\)
b) \(\left[\left(6x-72\right):2-84\right].28+5628=0\)
\(\left[\frac{6x}{2}-\frac{72}{2}-84\right].28+5628=0\)
\(\left[3x-36-84\right].28=-5628\)
\(3x-120=\frac{-5628}{28}\)
\(3x-120=-201\)
\(3x=-201+120\)
\(3x=-81\)
\(x=-27\)
vậy \(x=-27\)
\(\left(2600+6400\right)-3.X=1200\)
\(9000-3.X=1200\)
\(3.X=9000-1200\)
\(3.X=7800\)
\(X=7800:3\)
\(X=2600\)
(2600+6400)-3xX=1200
⇒ 9000-3xX=1200
⇒ 3xX=9000-1200=7800
⇒ X=7800:3=2600
⇒ X=2600