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3/229 x ( 2 + 1/433 ) - 1/229 x 432/433 - 4/229x433
= ( 3/229 x 867/433 ) - ( 432/99157 - 4/99157 )
= 2601/99157 - 432/99157 - 4/99157
= 5/229
\(M=\frac{3}{299}\cdot\left(2+\frac{1}{433}\right)-\frac{1}{299}\cdot\frac{432}{433}-\frac{4}{229.433}\)
\(M=\left(\frac{3}{229}\cdot\frac{867}{433}\right)-\left(\frac{432}{99157}-\frac{4}{99157}\right)\)
\(M=\frac{2601}{99157}-\frac{432}{99157}-\frac{4}{99157}\)
\(M=\frac{5}{229}\)
Bài 1:
a: \(A=y^3-4y^2+2y-8-y^3+4y^2-\dfrac{1}{2}y+2\)
\(=\dfrac{3}{2}y-6=\dfrac{3}{2}\cdot\dfrac{-2}{3}-6=-1-6=-7\)
b: \(x+1=5\)
\(B=x^5-x^4\left(x+1\right)+x^3\left(x+1\right)-x^2\left(x+1\right)+x\left(x+1\right)-2\)
=x-2
=4-2
=2
c: \(C=\dfrac{1}{229}\cdot\left(6+\dfrac{3}{433}\right)-\dfrac{1}{299}\cdot\dfrac{432}{433}-\dfrac{1}{229}\cdot\dfrac{4}{433}\)
\(=\dfrac{1}{299}\left(6+\dfrac{3}{433}-\dfrac{432}{433}-\dfrac{4}{333}\right)\)
\(=\dfrac{-5}{299}\)
