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\(\frac{1}{2}-\frac{1}{3}+\left(\frac{1}{2}x-\frac{1}{3}\right)=\frac{5}{6}\)
\(\frac{1}{6}+\left(\frac{1}{2}x-\frac{1}{3}\right)=\frac{5}{6}\)
\(\frac{1}{2}x-\frac{1}{3}=\frac{5}{6}-\frac{1}{6}\)
\(\frac{1}{2}x-\frac{1}{3}=\frac{2}{3}\)
\(\frac{1}{2}x=\frac{2}{3}+\frac{1}{3}\)
\(\frac{1}{2}x=1\)
\(x=2\)
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ta lấy 5 chữ số 1 cuối cùng chia cho 1001 ta đc: 11111:1001=11 dư 100
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b: \(=8+2\cdot3-7\cdot1.3+3\cdot\dfrac{5}{4}=8.65\)
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\(\left(x-1\right)^4=\left(x-1\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x-1=1\\x-1=-1\\x-1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=2\\x=0\\x=1\end{matrix}\right.\)
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a, Với \(x\ge\frac{2}{3}\)
\(P=\frac{1}{2}-\frac{1}{2}\left(x:\frac{1}{6}-\frac{1}{4}\right)-2\left|3x-2\right|\)
\(=\frac{1}{2}-\frac{1}{2}\left(6x-\frac{1}{4}\right)-2\left(3x-2\right)\)
\(=\frac{1}{2}-3x+\frac{1}{8}-6x+4=-9x+\frac{37}{8}\)
Với \(x< \frac{2}{3}\)
\(P=\frac{1}{2}-\frac{1}{2}\left(6x-\frac{1}{4}\right)-2\left(2-3x\right)=\frac{1}{2}-3x+\frac{1}{8}-4+6x=3x-\frac{27}{8}\)
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