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![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(a^2+b^2+2ab+2a+2b+1\)
\(=(a^2+2ab+b^2)+(2a+2b)+1\)
\(=(a+b)^2+2(a+b)+1^2=(a+b+1)^2\)
b)
\(3x(x-2y)+6y(2y-x)\)
\(=3x(x-2y)-6y(x-2y)=(3x-6y)(x-2y)=3(x-2y)(x-2y)\)
\(=3(x-2y)^2\)
c)
\(16xy+4y^2-9+16x^2\)
\(=(16x^2+16xy+4y^2)-9\)
\(=(4x+2y)^2-3^2=(4x+2y-3)(4x+2y+3)\)
d)
\(x^4+64y^8=(x^2)^2+(8y^4)^2=(x^2)^2+(8y^4)^2+2.x^2.8y^4-2x^2.8y^4\)
\(=(x^2+8y^4)^2-16x^2y^4=(x^2+8y^4)^2-(4xy^2)^2\)
\(=(x^2+8y^4-4xy^2)(x^2+8y^4+4xy^2)\)
e)
\(3x^2-7x+2=3x^2-6x-x+2=(3x^2-6x)-(x-2)\)
\(=3x(x-2)-(x-2)=(3x-1)(x-2)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
B1 :
a, B = (x+1)^2+(y-2)^2 = (99+1)^2+(102-2)^2 = 100^2+100^2 = 20000
b, = (2x^2+16x+32)-2y^2
= 2.(x+4)^2-2y^2
= 2.[(x+4)^2-y^2] = 2.(x+4-y).(x+4+y)
c, <=> (x^2-3x)+(2x-6) = 0
<=> (x-3).(x+2) = 0
<=> x-3=0 hoặc x+2=0
<=> x=3 hoặc x=-2
B2 :
P = (3-x).(x+3)/x.(x-3) = -(x+3)/x = -x-3/x
k mk nha
Bai 1
a)B=(x+1)2+(y-2)2
Voi x=99,y=102
=>B= 1002+1002
=20000
b)\(2x^2-2y^2+16x+32\)
=\(2\left[\left(x^2+8x+16\right)-y^2\right]\)
=\(2\left[\left(x+4\right)^2-y^2\right]\)
=2(x-y+4)(x+y+4)
c)\(x^2-3x+2x-6=0\)
=>x(x-3)+2(x-3)=0
=>(x-3)(x+2)=0
=>x=-2;3
Bai 2
\(P=\frac{9-x^2}{x^2-3x}\)
=\(-\frac{x^2-9}{x\left(x-3\right)}\)
=\(-\frac{\left(x-3\right)\left(x+3\right)}{x\left(x-3\right)}\)
=\(\frac{-x-3}{x}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1)x^3-x^2y-4x-4y=x^2\left(x-y\right)-4\left(x-y\right)=\left(x^2-2^2\right)\left(x-y\right)=\left(x^2-4x+4\right)\left(x-y\right)\)
\(2)x^3-3x^2+1-3x=\left(x^3+1\right)-3x\left(x-1\right)=\left(x+1\right)\left(x^2-x+1\right)-3x\left(x-1\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=2\left(x^2-y^2\right)-6\left(x+y\right)=2\left(x-y\right)\left(x+y\right)-6\left(x+y\right)=\left(x+y\right)\left(2x-2y-6\right)\) Đảm bảo chuẩn ko cần chỉnh (•••
check mk nhá
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,\\ a,=x\left(2x+3y-5\right)\\ b,=x\left(x-2y\right)+\left(x-2y\right)=\left(x+1\right)\left(x-2y\right)\\ 2,\\ a,\Leftrightarrow x\left(x+4\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\\ b,\Leftrightarrow x\left(x-2y\right)+\left(x-2y\right)=0\\ \Leftrightarrow\left(x+1\right)\left(x-2y\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=2y\left(y\in R\right)\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A. x2 - 3xy
= x (x - 3y)
B. (x + 5)2 - 9
= (x + 5) - 32
= (x + 5 + 3) (x + 5 - 3)
= ( x + 8) ( x + 2)
C. xy + xz - 2y - 2z
= (xy + xz) - (2y + 2z)
= x (y + z) - 2 (y + z)
= (x - 2) (y + z)
![](https://rs.olm.vn/images/avt/0.png?1311)
a2 + b2 + 2ab + 2a + 2b + 1
= ( a2 + 2ab + b2 ) + ( 2a + 2b ) + 1
= ( a + b )2 + 2( a + b ) + 12
= ( a + b + 1 )2
3x( x - 2y ) - 6y( 2y - x )
= 3x( x - 2y ) + 6y( x - 2y )
= 3( x - 2y )( x + 2y )
x2 + 2x - 3
= x2 - x + 3x - 3
= x( x - 1 ) + 3( x - 1 )
= ( x - 1 )( x + 3 )
a) \(a^2+b^2+2ab+2a+2b+1\)
\(=\left(a^2+2ab+b^2\right)+\left(2a+2b\right)+1\)
\(=\left(a+b\right)^2+2\left(a+b\right)+1\)
\(=\left(a+b+1\right)^2\)
b) \(3x\left(x-2y\right)-6y\left(2y-x\right)\)
\(=3x\left(x-2y\right)+6y\left(x-2y\right)\)
\(=3\left(x-2y\right)\left(x+2y\right)\)
c) \(x^2+2x-3=x^2-x+3x-3\)
\(=\left(x^2-x\right)+\left(3x-3\right)\)
\(=x\left(x-1\right)+3\left(x-1\right)\)
\(=\left(x-1\right)\left(x+3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+y\right)\left(x+2y\right)\left(x+3y\right)\left(x+4y\right)+y^4\)
\(=\left(x^2+5xy+4y^2\right)\left(x^2+5xy+6y^2\right)+y^4\)
\(=\left(x^2+5xy\right)^2+10y^2\left(x^2+5xy\right)+24y^4+y^4\)
\(=\left(x^2+5xy+5y^2\right)^2\)
a, a2+b2+2ab+2a+2b+1=(a+b+1)2
b,3x(x-2y)+6y(2y-x)=3x(x-2y)-6y(x-2y)
=3(x-2y)(x-2y)=3(x-2y)2
c, 16xy +4y2-9 +16x2=(16x2+16xy+4y2)-32
=(4x-2y)2-32=(4x-2y+3)(4x-2y-3)