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A, 11/4 x 2/5 : 3/7
= 11/10 : 3/7
= 77/30
B, 4/9 : 2/9 x 6/7
= 2 x 6/7
= 12/7
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\(A=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(A=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(A=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(A=\frac{4^{15}+4^{10}}{4^3+4^{11}}\)
\(A=\frac{4^{10}\left(4^5+1\right)}{4^6\left(4^5+1\right)}\)
\(A=\frac{4^{10}}{4^6}=4^4=256\)
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tự giải đi em bài này học sinh trường chị biết giải hết đó:v
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46 . 95 + 69 . 120 / 84 . 312 - 611
= ( 22 )6. ( 32 ) 5 + (2 . 3 ) 9 . 23 . 3 . 5 / ( 23 ) 4 . 312 - ( 2 . 3 ) 11
= 2^12.3^10+2^9.3^9.2^3.3.5 / 2^12.3^12-2^11.3^11
= 2^12.3^10+2^12.3^10.5 / 2^11.3^11.(2.3-1)
= 2^12.3^10.(1+5) / 2^11.3^11. (6-1)
= 2^12.3^10.6 / 2^11.3^11.5
= 2^13.3^11 / 2^11.3^11.5
= 2^2/5
=4/5
\(B=\frac{6}{91}+\frac{8}{273}+\frac{4}{525}-\frac{11}{350}\)
\(=\frac{18}{273}+\frac{8}{273}+\frac{8}{1050}-\frac{33}{1050}\)
\(=\left(\frac{18}{273}+\frac{8}{273}\right)+\left(\frac{8}{1050}-\frac{33}{1050}\right)\)
\(=\frac{4}{42}-\frac{1}{42}\)
\(=\frac{1}{14}\)