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E = \(\frac{\left(2^2\right)^6.\left(3^2\right) ^5+\left(2.3\right)^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
E = \(\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}-2^{11}.3^{11}}\)
E = \(\frac{2^{12}.3^{10}+2^{13}.3^{10}.5}{-2^{11}.3^{11}.\left(2.3+1\right)}\)
E = \(\frac{2^{12}.3^{10}.\left(1+5\right)}{-2^{11}.3^{11}.7}\)
E = \(\frac{2^{12}.3^{10}.6}{-2^{11}.3^{11}.7}\)
E=\(\frac{-2^{11}.\left(-2\right).3^{10}.6}{-2^{11}.3^{10}.3.7}\)
E = \(\frac{-2.6}{3.7}=-\frac{4}{7}\)
Vậy E = -4/7
Ý F bn lm tương tự nha
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`(-9/5).(-9/11).(-13/14).2/5`
`=((-9).(-9).(-13).2)/(5.11.14.5)`
`=2106/3850=1053/1925`
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\(\frac{1}{3}\left(x-1\right)+\frac{2}{5}\left(x+1\right)=0\)
\(\frac{1}{3}x-\frac{1}{3}+\frac{2}{5}x+\frac{2}{5}=0\)
\(\frac{11}{15}x+\left(\frac{2}{5}-\frac{1}{3}\right)=0\)
\(\frac{11}{15}x+\frac{1}{15}=0\)
\(\frac{1}{15}\left(11x+1\right)=0\)
\(11x+1=0\)
\(\Rightarrow x=-\frac{1}{11}\)
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Ta có:
\(=\frac{6}{12}+\frac{6}{12}+\frac{20}{12}-\frac{9}{12}\)
\(=\frac{29}{12}\)
Hok tốt
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$\dfrac{2}{3}=\dfrac{6}{9}\\\dfrac{2}{6}=\dfrac{3}{9}\\\dfrac{3}{2}=\dfrac{9}{6}\\\dfrac{6}{2}=\dfrac{9}{3}$
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Mk lm đc câu nào hay câu đó nha
A = 3/8 + [ 11/17 + (-3/8 ) ]
= [ 3/8 + ( -3 /8 ) ] + 11/17
= 0 + 11/17
= 11/17
C = 1/3 . 17/21 + 4/21 . 1/3 - 5/12
= 1/3 ( 17/21 + 4/21 ) - 5/12
= 1/3 - 5/12
= -1/12
D = 1/7 + 4/9 + 6/7 + 25/45
= ( 1/7 + 6/7 ) + ( 4/9 + 25/45 )
= 1 +1
= 2
Mk chỉ lm đc thế này thôi mong thông cảm hjhj
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1. \(\frac{\left(0,6\right)^5}{\left(0.2\right)^5}=\left(\frac{0.6}{0.2}\right)^5=\left(3\right)^5=243\)
2.\(\frac{6^3+3.6^2+3^3}{-13}=\frac{6^2\left(6+3\right)+3^3}{-13}=\frac{6^2.9+3^2.3}{-13}\)
\(\Leftrightarrow\frac{6^2.9+3^2.3}{-13}=\frac{3^2.39}{-13}=3^2.\left(-3\right)=-27\)
TL ;
\(\frac{9^2.9^3.6}{3^{11}}=\frac{\left(3^2\right)^2.\left(3^2\right)^3.3.2}{3^{11}}=\frac{3^4.3^6.3.2}{3^{11}}=\frac{3^{11}.2}{3^{11}}=2.\)
HT