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Cho A = \(\frac{5}{4.3}\) + \(\frac{14}{3.23}\) + \(\frac{16}{23.13}\) + \(\frac{7}{13.46}\) . Tìm A
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13.75 + 23.13 - 120
= 13.(75 + 23) - 120
= 13.98 - 120
= 1274 - 120
= 1154
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\(9\frac{8}{23}-\left(5\frac{7}{12}+14\frac{8}{23}\right)\)
\(< =>\frac{215}{23}-\left(\frac{67}{12}+\frac{330}{23}\right)\)
\(< =>\frac{215}{23}-\frac{5501}{276}\)
\(< =>\frac{-127}{12}\)
chuc ban hoc tot nhe >.<
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49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\) )
= \(\frac{1135}{23}\) - (\(\frac{167}{32}\) +\(\frac{330}{23}\) )
= \(\frac{1135}{23}\) - \(\frac{14401}{736}\)
=\(\frac{953}{32}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=\frac{1135}{23}\left(\frac{135}{32}+\frac{330}{23}\right)\)
\(=\frac{1135}{23}.\frac{13665}{736}\)
\(=916,2201678\)
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\(\frac{23.13+23}{14.47-14}=\frac{23.14}{14.46}=1128\)