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\(=\frac{3+\frac{3}{4}-\frac{3}{19}}{\frac{5}{2}+\frac{5}{8}-\frac{5}{38}}.\frac{15+\frac{15}{34}+\frac{15}{17}-\frac{15}{144}}{2+\frac{2}{34}+\frac{2}{17}-\frac{2}{144}}+2018\)
\(=\frac{3\left(1+\frac{1}{4}-\frac{1}{19}\right)}{\frac{5}{2}\left(1+\frac{1}{4}-\frac{1}{19}\right)}.\frac{15\left(1+\frac{1}{34}+\frac{1}{17}-\frac{1}{144}\right)}{2\left(1+\frac{1}{34}+\frac{1}{17}-\frac{1}{144}\right)}+2018\)
\(=\frac{3}{\frac{5}{2}}.\frac{15}{2}+2018\)
\(=\frac{6}{5}.\frac{15}{2}+2018\)
\(=9+2018=2027\)
\(\frac{3+0,75-\frac{3}{19}}{\frac{5}{2}+0,625-\frac{5}{38}}\) . \(\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{2}{17}-\frac{2}{144}+\frac{1}{17}}\)+2018
=\(\frac{3+\frac{3}{4}-\frac{3}{19}}{\frac{5}{2}+\frac{5}{8}-\frac{5}{38}}\) . \(\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{2}{17}-\frac{2}{144}+\frac{2}{34}}\)+2018
=\(\frac{3\left(1+\frac{1}{4}-\frac{1}{19}\right)}{5\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{38}\right)}\) . \(\frac{15\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}{2\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}\)+2018
=\(\frac{6\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{38}\right)}{5\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{38}\right)}\) . \(\frac{15\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}{2\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}\)+2018
=\(\frac{6}{5}\) . \(\frac{15}{2}\)+2018
=9+2018
=2027
Thật ra đề không sai đâu nha các bạn chúng ta cần phân tích để tử số giống mẫu số rồi rút gọn chúng ta sẽ ra được kết quả
Chúc các bạn học tốt
Ta có: \(\left(2\dfrac{2}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\)
\(=\left(\dfrac{32}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\)
\(=-\dfrac{\dfrac{32}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}}{\dfrac{3}{17}}=\dfrac{-32}{15}\cdot\dfrac{9}{32}=-\dfrac{3}{5}\)
a) \(\frac{-77}{143}+\frac{65}{143}-\frac{66}{143}+\frac{7}{22}\)
= \(\frac{-78}{143}+\frac{7}{22}\)= \(\frac{-6}{11}+\frac{7}{22}\)= \(\frac{-12}{22}+\frac{7}{22}\)
= \(\frac{-5}{22}\)
b) \(\frac{-4}{5}-\frac{20}{170}+\frac{51}{170}+\frac{150}{170}\)= \(\frac{-4}{5}-\frac{221}{170}\)
\(\frac{-4}{5}-\frac{13}{10}\)= \(\frac{-8}{10}-\frac{13}{10}\)=\(\frac{-21}{10}\)
Ta có:
\(\frac{A}{2}=\frac{3^3}{2}-\frac{5^3}{6}+\frac{7^3}{12}-\frac{9^3}{20}+\frac{11^3}{30}-\frac{13^3}{42}+\frac{15^3}{56}-\frac{17^3}{72}+...+\frac{199^3}{9900}\)
\(=3^2.\left(1+\frac{1}{2}\right)-5^2.\left(\frac{1}{2}+\frac{1}{3}\right)+7^2.\left(\frac{1}{3}+\frac{1}{4}\right)-9^2.\left(\frac{1}{4}+\frac{1}{5}\right)+...+199^2.\left(\frac{1}{99}+\frac{1}{100}\right)\)
\(=3^2+\left(\frac{3^2}{2}-\frac{5^2}{2}\right)-\left(\frac{5^2}{3}-\frac{7^2}{3}\right)+\left(\frac{7^2}{4}-\frac{9^2}{4}\right)-\left(\frac{9^2}{5}-\frac{11^2}{5}\right)+...+\left(\frac{197^2}{99}-\frac{199^2}{99}\right)+\frac{199^2}{100}\)
\(=3^2-8+8-8+...+8+\frac{199^2}{100}=3^2+\frac{199^2}{100}< 3^2+\frac{199.200}{100}=9+398=407\)
\(\Rightarrow A< 407.2=814\)
\(\left(\frac{15}{17}\right)^5.\left(\frac{15}{17}\right)^6=\left(\frac{15}{17}\right)^{5+6}=\left(\frac{15}{17}\right)^{11}\)
sau đó bạn chỉ cần bấm máy là ra kết quả
k cho mik nha
cái đầu là (\(\frac{15}{17}\))\(^5\)nha các bạn, các bạn trả lời giúp mk, mk đg cần gấp