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\(a.\sqrt{343a}+\sqrt{63a}-\sqrt{28a}=\sqrt{49.7a}+\sqrt{9.7a}-\sqrt{4.7a}=7\sqrt{7a}+3\sqrt{7a}-2\sqrt{7a}=8\sqrt{7a}\) \(b.-\sqrt{36b}-\dfrac{1}{3}\sqrt{54b}+\dfrac{1}{5}\sqrt{150b}=-6\sqrt{b}-3\sqrt{6b}+\sqrt{6b}=-6\sqrt{b}-2\sqrt{6b}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=-6\sqrt{b}-\dfrac{1}{3}\cdot3\sqrt{3b}+\dfrac{1}{5}\cdot5\sqrt{6b}\)
\(=-6\sqrt{b}-\sqrt{3}\cdot\sqrt{b}+\sqrt{6}\cdot\sqrt{b}\)
\(=\sqrt{b}\left(-6-\sqrt{3}+\sqrt{6}\right)\)
c: \(=\sqrt{\left(5+2\sqrt{6}\right)^2}+\sqrt{\left(5-2\sqrt{6}\right)^2}\)
\(=5+2\sqrt{6}+5-2\sqrt{6}=10\)
d: \(A=\sqrt{\sqrt{5}-\sqrt{3-2\sqrt{5}+3}}\)
\(=\sqrt{\sqrt{5}-\sqrt{6-2\sqrt{5}}}\)
\(=\sqrt{\sqrt{5}-\sqrt{5}+1}=1\)
e: \(B=\sqrt{6+2\sqrt{5-2\sqrt{3}-1}}\)
\(=\sqrt{6+2\cdot\left(\sqrt{3}-1\right)}=\sqrt{4+2\sqrt{3}}=\sqrt{3}+1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(C=-6\sqrt{b}-\sqrt{6}.\sqrt{b}+\sqrt{6}b=-6\sqrt{b}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=3\sqrt{3}-2\sqrt{3}+4\sqrt{3}-5\sqrt{3}=2\sqrt{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=2\sqrt{20\sqrt{3}}-2\sqrt{5\sqrt{3}}-3\cdot\sqrt{20\sqrt{3}}\)
\(=4\sqrt{5\sqrt{3}}-2\sqrt{5\sqrt{3}}-6\sqrt{5\sqrt{3}}=-4\sqrt{5\sqrt{3}}\)
b: \(=2\sqrt{5\sqrt{3}}-4\sqrt{2\sqrt{3}}-6\sqrt{5\sqrt{3}}=-4\sqrt{5\sqrt{3}}-4\sqrt{2\sqrt{3}}\)
đề đúng chưa bạn?