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(-12)2.x = 56 + 10.13.x
144.x = 56 + 130.x
144x – 130 x = 56
14x = 56
x = 56: 14
x = 4
Vậy x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
122-x = 56+10.13.x
144-x=56+130.x
144-x-130.x=56
14.x=56
x=56:14
x=4
![](https://rs.olm.vn/images/avt/0.png?1311)
(-12)^2.x =56+10.13.x
144.x =56+130.x
144.x-130.x =56
14.x =56
x=4
Vậy x=4.
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(x+5\right).\left(x-4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+5=0\\x-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0-5\\x=0+4\end{cases}\Rightarrow}\orbr{\begin{cases}x=-5\\x=+4\end{cases}}}\)
Vậy \(x\in\){-5 ; 4}
b) \(\left(x-5\right)^6=\left(x-5\right)^8\)
Ta có : \(0^n=0\)\(;\)\(1^n=1\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x-5=1\end{cases}\Rightarrow\orbr{\begin{cases}x=0+5\\x=1+5\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)
Vậy \(x\in\){5 ; 6}
a) (x + 5) . (x - 4) = 0
x + 5 = 0 x = -5
<=> <=>
x - 4 = 0 x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
<=> 144x = 56 + 130x
<=> 144x - 130x = 56
<=> 14x = 56
<=> x = 56 : 14
<=> x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
( -12 )2 . x = 56 + 10.13 . x
144 . x = 56 + 130.x
56 + 130 . x = 144. x
130 . x = 144.x - 56
Ta thay lần lượt từ 1, 2, 3,...khi đó x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
(-12)2.x = 56 + 10.13.x
=> 144.x = 56 + 130.x
=> 144.x-130.x=56
=> 14.x=56
=> x=56:14
=> x=4
(-12)^2.x=56+10.13.x
=>144.x=56+130x
=>144x-130x=56
=>14x=56
=>x=56:14
=>x=4
=>144x=56+130x
=>144x-130x=56
=>14x=56
=>x=56:14
=>x=4
(-12)2.x=56+10.13.x
144.x=56+130.x
14.x=56
x=56:14
x=4
Tick cho tớ nha các bn