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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 3S = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + .....+ 50.51.(52 -49)
= 1.2.3 - 0 + 2.3.4 - 1.2.3 + 3.4.5 -2.3.4 + .....+ 50.51.52 - 49.50.51
3S = 50.51.52
S = 50.17.52 =44200
![](https://rs.olm.vn/images/avt/0.png?1311)
Nhân cả 2 vế của S với 3 ta được :
3S = 3(1.2 + 2.3 + 3.4 + ..... + 49.50)
= 1.2.3 + 2.3.3 + 3.4.3 + ... + 49.50.3
= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + .... + 49.50.(51 - 48)
= 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + .... + 49.50.51 - 48.59.50
= (1.2.3 - 1.2.3) + (2.3.4 - 2.3.4) + ......... + (48.49.50 - 48.49.50) + 49.50.51
= 49.50.51
=> S = 49.50.51/3 = 41650
![](https://rs.olm.vn/images/avt/0.png?1311)
A=1.2+2.3+...+49.50
3A=1.2.3+2.3.3+...+49.50.3
3A=1.2.(4-1)+2.3.(5-2)+....+49.50.(51-48)
3A=1.2.4-1.2.1+2.3.5-2.3.2+...+49.50.51-49.50.48
3A=49.50.51
=>A=49.25.51
=>A=62475
A=1.2+2.3+...+49.50
3A=1.2.3+2.3.3+...+49.50.3
3A=1.2.(4-1)+2.3.(5-2)+....+49.50.(51-48)
3A=1.2.4-1.2.1+2.3.5-2.3.2+...+49.50.51-49.50.48
3A=49.50.51
=>A=49.25.51
=>A=62475
![](https://rs.olm.vn/images/avt/0.png?1311)
S=1.2+2.3+3.4+.....+N(N+1)
3S=1.2(3-0)+2.3(4-1)+....+N.(N+1)+N(N+1)-(N+2)
3S=1.2.3+2.3.4+3.4.5+.+N(N+1)+(N+2)
3S=N(N+1)+(N+2)
S=N(N+1)+(N+2)/3
3.A=1.2.(3-0)+2.3.(4-1)+3.4.(5 -2)...+ n.(n+1) . ((n+2) - (n-1))
3.A=1.2.3+2.3.4+3.4.5+...+ (n-1) . n. (n+1)+ n. (n+1). (n+2) -
0.1.2 -1.2.3 -2.3.4 -3.4.5 -...(n-1)n(n+1)
3A=n.(n+1).(n+2)
A=n.(n+1).(n+2)\3
Ai tk mình mk tk lại nha
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
S=1.2+2.3+3.4+...+99.100
3S=1.2.3+2.3.3+3.4.3+...+99.100.3
3S=1.2.3+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3S=99.100.101
S=33.100.101
S=3333.100
S=333300
Gọi A là biểu thức ta có:
A = 1.2+2.3+3.4+......+99.100
Gấp A lên 3 lần ta có:
A . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3
A . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98)
A . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100
A . 3 = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
A = 333 300
![](https://rs.olm.vn/images/avt/0.png?1311)
1.2+2.3+3.4.....+n.(n+1)=A
ta có
3.A=1.2.(3-0)+2.3.(4-1)+3.4.(5 -2)...+ n.(n+1) . ((n+2) - (n-1))
3.A=1.2.3+2.3.4+3.4.5+...+ (n-1) . n. (n+1)+ n. (n+1). (n+2) -
0.1.2 -1.2.3 -2.3.4 -3.4.5 -...(n-1)n(n+1)
3A=n.(n+1).(n+2)
A=n.(n+1).(n+2)\3
![](https://rs.olm.vn/images/avt/0.png?1311)
Trước tiên, chúng ta cần có lý thuyết về biến đổi phân số.
\(\dfrac{b-a}{a\cdot b}=\dfrac{1}{a}-\dfrac{1}{b}\)
Ta có:
\(S=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{2017\cdot2018}\)
\(S=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2017}-\dfrac{1}{2018}\)
\(S=1+\left(-\dfrac{1}{2}+\dfrac{1}{2}\right)+\left(-\dfrac{1}{3}+\dfrac{1}{3}\right)+...-\dfrac{1}{2018}\)
\(S=1-\dfrac{1}{2018}\)
\(S=\dfrac{2017}{2018}\)
=1/1.2+1/2.3+1/3.4+...1/2017.2018
=1/1-1/2+1/2-1/3+1/3-1/4+...+1/2017-1/2018
=1-1/2018
=2018/2018-1/2018
=2017/2018
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 3S = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + .....+ 50.51.(52 -49)
= 1.2.3 - 0 + 2.3.4 - 1.2.3 + 3.4.5 -2.3.4 + .....+ 50.51.52 - 49.50.51
3S = 50.51.52
S = 50.17.52 =44200
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