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1. a. 9.(x-2)+1=2-2x
=> 9x-18+1=2-2x
=> 9x+2x = 2+18-1
=> 11x = 19
=> x=19/11
b. 9|x| = 45
=> |x| = 5
=> x=5 hoặc x=-5
c. 9:|x|=3
=> |x| = 3
=> x=3 hoặc x=-3
d. 5.(1-x)+2x=9-2x
=> 5-5x+2x=9-2x
=> -5x+2x+2x=9-5
=> -x=4
=> x=-4
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a,( x - 29 ) - ( 17 - 38 ) = -9
( x - 29 ) + 21 = - 9
x - 29 = - 9 - 21
x - 29 = - 30
x = -30 + 29
x = -1
c, ( 27 - x ) + ( 15 + x ) = - 24
27 - x + 15 + x = -24
- x + x = -24-27-15
Vô lí vì 0 ko bằng -66
Vậy \(x\in\varnothing\)
d, |2x - 7|- 9 =20
|2x-7|=11
* 2x-7=11 * 2x-7=-11
2x=11+7 2x=-11+7
2x=18 2x=-4
x=18:2 x=-4:2
x=9 x=-2
Vậy x=9 hoặc x=-2
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>-2x=9-17=-8
hay x=4
b: =>15-x=-10
hay x=25
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
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4x-2x+x-27:9=33
2x+x-27:9=33
3x-27:9=33
3x-27=33×9=297
3x=297+27=324
x=324÷3=108
![](https://rs.olm.vn/images/avt/0.png?1311)
b: =>15-x=-10
hay x=25
a: =>-2x+17=9
=>-2x=-8
hay x=4
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(-x+3=2x+9\\ \Rightarrow-x-2x=9-3\\ \Rightarrow-3x=6\\ \Rightarrow x=-\dfrac{6}{3}\\ \Rightarrow x=-2\)
Vậy \(x=-2\)
\(-x-5=-2x+11\\ \Rightarrow-x+2x=11+5\\ \Rightarrow x=16\)
Vậy \(x=16\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\text{ a, 5-(10x)=-7}\)
\(\Rightarrow\) 10x=5-(-7)
\(\Rightarrow\) 10x=12
\(\Rightarrow\) x=12:10
\(\Rightarrow\) x=1,2
b, (x-5).(2x+8)=0
\(\Rightarrow\) x-5=0 hoặc 2x+8=0
\(\Rightarrow\) x =0+5 \(\Rightarrow\) 2x =0+8
\(\Rightarrow\) x =5 \(\Rightarrow\) 2x =8
\(\Rightarrow\) x =8:2
\(\Rightarrow\) x =4
vậy x\(\in\){5;4}
c, 2x-9=-8+9
\(\Rightarrow\) 2x-9=1
\(\Rightarrow\) 2x =1+9
\(\Rightarrow\) 2x =10
\(\Rightarrow\) x =10:2
\(\Rightarrow\) x =5
d, |x-9|.(-8)=-16
\(\Rightarrow\)|x-9| =-16:(-8)
\(\Rightarrow\)|x-9| =2
\(\Rightarrow\) x-9 =\(\hept{\begin{cases}2\\-2\end{cases}}\)
trường hợp 1: x-9=2
\(\Rightarrow\) x =2+9
\(\Rightarrow\) x =11
trường hợp 2: x-9=-2
\(\Rightarrow\) x =-2+9
\(\Rightarrow\) x =7
vậy x \(\in\){11;7}
# học tốt #
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>-2x+17=9
=>-2x=-8
hay x=4
b: =>15-x=-10
hay x=25
c: =>7x=-4
hay x=-4/7
d: =>\(9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
g: \(\Leftrightarrow2x-4+5⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{3;1;7;-3\right\}\)
\(\left|9+x\right|=2x\)
\(\left|9+x\right|-2x=0\)
\(\left\{{}\begin{matrix}x=9,x\ge-9\\x=-3,x< -9\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x=9\\\varnothing\end{matrix}\right.\)
\(x=9\)