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a: \(A=\left[111\cdot\left(38\cdot3-133\right)\right]\cdot2018\)
\(=111\cdot\left(-19\right)\cdot2018=-4255962\)
b: \(B=\left[25\left(1+3\cdot3-5\cdot2\right)\right]:20182019\)
\(=25\left(1+9-10\right):20182019=0\)
c: \(C=\dfrac{\left[244\left(395-195\right)\right]}{122\cdot200}=\dfrac{244}{122}=2\)
d: \(D=\dfrac{355\cdot45\cdot55}{11\cdot9\cdot7}=\dfrac{355\cdot5\cdot5}{7}=\dfrac{8875}{7}\)
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a/ 12x - 33 = 32 . 32
=> 12x - 33 = 35 = 243
=> 12x = 243 + 33 = 276
=> x = 276 : 12 = 23
b/ 148 + (78 + x) = 244
=> 78 + x = 148 - 244 = -96
=> x = -96 - 78 = -174
c/ 45 - x = 49 + 52
=> 45 - x = 101
=> x = 45 - 101 = -56
d/ 707 - 3(x + 34) = 407
=> 3(x + 34) = 707 - 407 = 300
=> x + 34 = 300 : 3 = 100
=> x = 100 - 34 = 66
e/ 25.3 - x = 104
=> 75 - x = 104
=> x = 75 - 104 = -29
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a, 1230 : 3(x – 20) = 10
3(x – 20) = 123
x – 20 = 41
x = 61
b, 250 – 10.(24 – 3x):15 = 244
10.(24 – 3x):15 = 6
10.(24 – 3x) = 90
24 – 3x = 9
3x = 15
x = 5
c, 4 x 3 + 15 = 47
4 x 3 = 32
x 3 = 8 = 2 3
x = 2
d, 65 - 4 x + 2 = 2014 0
65 - 4 x + 2 = 1
4 x + 2 = 64 = 4 3
x + 2 = 3
x = 1
e, 4 . 2 x - 3 = 125
4 . 2 x = 128
2 x = 32 = 2 5
x = 5
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[(x^2+54)-32]*2=244
(x^2+54)-32=244/2
(x^2+54)-32=122
x^2+54=122+32
x^2+54=154
x^2=154-54
x^2=100
=> x=10 hoặc x=-10
[(x2+54)-32]*2=244
(x2+54)-32=244/2
(x2+54)-32=122
x2+54=122+32
x2+54=154
x2=154-54
x2=100=102
=>x=10
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`60 + 2 . ( x + 3 ) = 244`
`2 . (x + 3 ) = 244 - 60`
`2. ( x + 3 ) = 184`
`x + 3 = 184 : 2`
`x + 3 = 92`
`x = 92 - 3`
`x = 89`
\(60+2\cdot\left(x+3\right)=244\\ 2\cdot\left(x+3\right)=244-60\\ 2\cdot\left(x+3\right)=184\\ x+3=184:2\\ x+3=92\\ x=92-3\\ x=89.\)