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6: =x^2-7xy+5xy-35y^2
=x(x-7y)+5y(x-7y)
=(x-7y)(x+5y)
7: =x^2-2xy-8xy+16y^2
=x(x-2y)-8y(x-2y)
=(x-2y)(x-8y)
8: =3x^2-6xy-4xy+8y^2
=3x(x-2y)-4y(x-2y)
=(x-2y)(3x-4y)
9: =4x^2+4xy+y^2-16y^2
=(2x+y)^2-16y^2
=(2x+y-4y)(2x+y+4y)
=(2x-3y)*(2x+5y)
10: =2(x^2+5xy+4y^2)
=2(x+y)(x+4y)
11: =5x(x+2y+y^2)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Làm tính nhân
(4x3+3xy2-2y3).(3x2-5xy-6y2)
=12x5+12y5-20x4y-36x2y3-8xy4
Phân tích đa thức thành nhân tử
10x3+5x2y-10x2y-10xy2+5y3
=10x3-5x2y-10xy2+5y3
=5(2x3-x2y-2xy2+y3-)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) \(y\left(x-1\right)=x^2+2\)
\(\Leftrightarrow x^2+2-y\left(x-1\right)=0\)
\(\Leftrightarrow x^2-1-y\left(x-1\right)+3=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+1\right)-y\left(x-1\right)=-3\)
\(\Leftrightarrow\left(x-1\right)\left(x+1-y\right)=-3\)
...
b ) \(3xy-5x-2y=3\)
\(\Leftrightarrow9xy-15x-6y=9\)
\(\Leftrightarrow9xy-15x-6y+10=19\)
\(\Leftrightarrow3y\left(3x-2\right)-5\left(3x-2\right)=19\)
\(\Leftrightarrow\left(3y-5\right)\left(3x-2\right)=19\)
...
c ) \(x^2-10xy-11y^2=13\)
\(\Leftrightarrow x^2-11xy+xy-11y^2=13\)
\(\Leftrightarrow x\left(x-11y\right)+y\left(x-11y\right)=13\)
\(\Leftrightarrow\left(x+y\right)\left(x-11y\right)=13\)
...
d ) \(xy-2=2x+3y\)
\(\Leftrightarrow xy-2-2x-3y=0\)
\(\Leftrightarrow y\left(x-3\right)-2\left(x-3\right)-8=0\)
\(\Leftrightarrow\left(y-2\right)\left(x-3\right)=8\)
...
e ) \(5xy+x+2y=7\)
\(\Leftrightarrow5xy+x+2y-7=0\)
\(\Leftrightarrow5x\left(y+\dfrac{1}{5}\right)+2\left(y+\dfrac{1}{5}\right)-\dfrac{37}{5}=0\)
\(\Leftrightarrow\left(5x+2\right)\left(y+\dfrac{1}{5}\right)=\dfrac{37}{5}\)
\(\Leftrightarrow\left(5x+2\right)\left(5y+1\right)=37\)
...
P/s : Vì bài dài nên việc tìm x , y ( lập bảng ) bạn tự làm nhé
Thanks
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5x^3-5xy^2+10xy-5x\)
\(=5x\left(x^2-y^2+2y-1\right)\)
\(=5x\left[x^2-y^2+y+y-1\right]\)
\(=5x\left[x^2-y\left(y-1\right)+\left(y-1\right)\right]\)
\(=5x\left[x^2-\left(y+1\right)\left(y-1\right)\right]\)
\(=5x\left[x^2-\left(y^2-1^2\right)\right]\)
\(=5x\left[\left(x-y\right)\left(x+y\right)+1\right]\)
Lâu k làm, sai thông cảm
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5x^2y-10xy^2+5xy=5xy\left(x-2y+1\right)\)
\(5xy\left(x-2y\right)\)