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12.68+34.18-34-142
12.2.34+34.18-34.1-142
=24.34+34.18-34.1-142
=34.(24+18-1)-142
=34.41-142
=1394-142
=1252
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12. 68 + 34. 18 - 34- 142
=12.2.34+34.18+108
=24.34+34.18+108
=34.(24+18)+108
=34.42+108
=1428+108
=1536
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(34 - 53 + 28) - (34 - 53 - 21)
= 34 - 53 + 38 - 34 + 53 + 21
= (34 - 34) - (53 - 53) + (38 + 21)
= 0 - 0 + 59
= 59
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a) 310 . 315 : 322 + 47 : 44
= 3(10 + 15 - 22 ) + 4(7-4)
= 33 + 43
= ( 3.4)3
=123
b)[ (52 . 53 ) - 72 . 2 ) : 2 ] . 6 = 7 . 25
[ (52 . 53 ) - 72 . 2 ) : 2 ] . 6 = 7 . 32
= 224
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Sửa đề: \(98+99+\dfrac{142}{144}\) \(\rightarrow\dfrac{98}{99}+\dfrac{143}{144}\)
Giải:
\(A=\dfrac{2}{3}+\dfrac{14}{15}+\dfrac{34}{35}+\dfrac{62}{63}+\dfrac{98}{99}+\dfrac{143}{144}+\dfrac{194}{195}\)
\(A=\left(1-\dfrac{1}{3}\right)+\left(1-\dfrac{1}{15}\right)+\left(1-\dfrac{1}{35}\right)+...+\left(1-\dfrac{1}{195}\right)\)
\(A=7-\left(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{195}\right)\)
\(A=7-\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{13.15}\right)\)
\(A=7-\left[\dfrac{1}{2}.\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{13.15}\right)\right]\)
\(A=7-\left[\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{13}-\dfrac{1}{15}\right)\right]\)
\(A=7-\left[\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{15}\right)\right]\)
\(A=7-\left[\dfrac{1}{2}.\dfrac{14}{15}\right]\)
\(A=7-\dfrac{7}{15}\)
\(A=\dfrac{98}{15}\)
Chúc bạn học tốt!
53 + 34 - 142
= 125 + 81 - 196
= 206 - 196
= 10
theo mình nghĩ là thế :))
\(5^3+3^4-14^2=125+81-196=10\)