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\(\Leftrightarrow3^{x-1}\left(1+3+3^2\right)=39\\ \Leftrightarrow3^{x-1}\cdot13=39\\ \Leftrightarrow3^{x-1}=3=3^1\\ \Leftrightarrow x-1=1\Leftrightarrow x=2\)
\(\Leftrightarrow3^x\cdot\dfrac{13}{3}=39\)
\(\Leftrightarrow x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\)
\(x.\frac{-1}{6}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{-1}{6}\)
\(x=\frac{-7}{2}\)
b) \(x:4\frac{1}{3}=-2,5\)
\(x:\frac{13}{3}=\frac{-5}{2}\)
\(x=\frac{-5}{2}.\frac{13}{3}\)
\(x=\frac{-65}{6}\)
c) \(5,5x=\frac{13}{15}=\frac{11}{2}x=\frac{13}{5}\)
\(x=\frac{13}{5}:\frac{11}{2}\)
\(x=\frac{26}{55}\)
d) \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
\(\frac{3x}{7}+1=\frac{-1}{28}.\left(-4\right)\)
\(\frac{3x}{7}+1=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1\)
\(\frac{3x}{7}=\frac{-6}{7}\)
\(\frac{3x}{7}=\frac{-6}{7}\Rightarrow\frac{3.\left(-2\right)}{7}=\frac{-6}{7}\)
Vậy x = -2
\(0,5x-\frac{2}{3}x=\frac{7}{12}\)\(\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(x.\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left|x^2+1\right|=2x^2\)
\(\Rightarrow\orbr{\begin{cases}x^2+1=2x^2\\x^2+1=-2x^2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x^2=1\\\text{loại}\end{cases}}\)
\(\Rightarrow x\in\left\{\pm1\right\}\)
b) \(\left|3x-1\right|+2x=\left|1-3x\right|+4\)
\(\left|3x-1\right|+2x=\left|3x-1\right|+4\)
\(2x=4\)
\(x=2\)
Vậy.....
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3x-32>-5x+1\)
\(\Leftrightarrow3x+5x>32+1\)
\(\Leftrightarrow8x>33\)
\(\Leftrightarrow x>\frac{33}{8}\)
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(3x - 24).3 = 2.54
(3x - 24).3 = 108
3x – 24 = 108 : 3
3x – 24 = 36
3x = 36 + 24
3x = 60
X = 60 : 3
X = 20
(3x-24).3=2.54
9x-72=108
9x =108-72
9x =36
x=36:4
x=9
nếu đúng thì tích đúng cho mình nha
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a) [ 3x-1] + 4x - 3 = 7
3x - 1 + 4x = 7 + 3 = 10
( 3 + 4 )x - 1 =10
7x - 1 = 10
7x=11
x=11/7
Câu tiếp theo làm tương tự nhé =))
) [ 3x-1] + 4x - 3 = 7
3x - 1 + 4x = 7 + 3 = 10
( 3 + 4 )x - 1 =10
7x - 1 = 10
7x=11
x=11/7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(2x-\frac{1}{3}\right)\left(3x+\frac{1}{2}\right)=0\)
\(=>\orbr{\begin{cases}2x-\frac{1}{3}=0\\3x+\frac{1}{2}=0\end{cases}}\)
\(=>\orbr{\begin{cases}2x=\frac{1}{3}\\3x=\frac{-1}{2}\end{cases}}\)
\(=>\orbr{\begin{cases}x=\frac{1}{6}\\x=\frac{-1}{6}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
xy - 3x + y = 13
x(y-3)+y-3=13-3
(x+1)(y-3)=10
=> x+1 và y-3 thuộc Ư(10)={-10;-5;-2;-1;1;2;5;10)
Ta có bảng sau:
x+1 | -10 | -1 | -5 | -2 | 1 | 10 | 2 | 5 |
y-3 | -1 | -10 | -2 | -5 | 10 | 1 | 5 | 2 |
x | -11 | -2 | -6 | -3 | 0 | 9 | 1 | 4 |
y | 2 | -7 | 1 | -2 | 13 | 4 | 8 | 5 |
Vậy.....................................