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\(3^x+2.3^{x-2}=297\)
\(\Rightarrow3^x\left(1+2.3^{-2}\right)=297\)
\(\Rightarrow3^x\left(1+2.\dfrac{1}{3^2}\right)=297\)
\(\Rightarrow3^x\left(1+\dfrac{2}{9}\right)=297\)
\(\Rightarrow3^x\left(\dfrac{9}{9}+\dfrac{2}{9}\right)=297\)
\(\Rightarrow3^x.\dfrac{11}{9}=297\)
\(\Rightarrow3^x=297:\dfrac{11}{9}=297.\dfrac{9}{11}=243\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\) (thỏa mãn)
Bạn cần ghi đầy đủ điều kiện của x,y đề mọi người hỗ trợ tốt hơn.
e) \(2^x+2^{x+3}=144\)
\(=>2^x+2^x.2^3=144\)
\(=>2^x.\left(1+2^3\right)=144\)
\(=>2^x.9=144\)
\(=>2^x=144:9\)
\(=>2^x=16=2^4\)
\(=>x=4\)
__________
f) \(3^x+3^{x+1}=108\)
\(=>3^x+3^x.3=108\)
\(=>3^x.\left(1+3\right)=108\)
\(=>3^x.4=108\)
\(=>3^x=108:4\)
\(=>3^x=27=3^3\)
\(=>x=3\)
\(#Wendy.Dang\)
b: Ta có: \(3^x+2\cdot3^{x-2}=297\)
\(\Leftrightarrow3^x=297:\dfrac{11}{9}=243\)
hay x=5
Lời giải:
a. $(x^2-9)(5x+15)=0$
$\Rightarrow x^2-9=0$ hoặc $5x+15=0$
Nếu $x^2-9=0$
$\Rightarrow x^2=9=3^2=(-3)^2$
$\Rightarrow x=3$ hoặc $-3$
Nếu $5x+15=0$
$\Rightarrow x=-3$
b.
$x^2-8x=0$
$\Rightarrow x(x-8)=0$
$\Rightarrow x=0$ hoặc $x-8=0$
$\Rightarrow x=0$ hoặc $x=8$
c.
$5+12(x-1)^2=53$
$12(x-1)^2=53-5=48$
$(x-1)^2=48:12=4=2^2=(-2)^2$
$\Rightarrow x-1=2$ hoặc $x-2=-2$
$\Rightarrow x=3$ hoặc $x=0$
d.
$(x-5)^2=36=6^2=(-6)^2$
$\Rightarrow x-5=6$ hoặc $x-5=-6$
$\Rightarrow x=11$ hoặc $x=-1$
e.
$(3x-5)^3=64=4^3$
$\Rightarrow 3x-5=4$
$\Rightarrow 3x=9$
$\Rightarrow x=3$
f.
$4^{2x}+2^{4x+3}=144$
$2^{4x}+2^{4x}.8=144$
$2^{4x}(1+8)=144$
$2^{4x}.9=144$
$2^{4x}=144:9=16=2^4$
$\Rightarrow 4x=4\Rightarrow x=1$
a)x=243:3 b) 5x=56:625 c)2x=128:24 d)3x+2=18:2
x=81 5x=28/263 2x=16/3 3x+2=9
x=28/263:5 x=16/3:2 3x=9-2
x=28/1315 x=8/3 3x=7=>x=7/3
a) 3x = 243
x = 243 : 3
x = 81
b ) 56 : 5x = 625
5x = 56 : 625
5x = 56/625
x = 56/625 : 5
x = 56/3125
Bài 1:
a) Ta có: \(x\left(x^2-4\right)=0\)
\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{0;2;-2\right\}\)
b) Ta có: \(\left(2x-3\right)+\left(-3x\right)-\left(x-5\right)=40\)
\(\Leftrightarrow2x-3-3x-x+5=40\)
\(\Leftrightarrow-2x+2=40\)
\(\Leftrightarrow-2x=38\)
hay x=-19
Vậy: x=-19
Bài 2:
a) Ta có: \(-45\cdot12+34\cdot\left(-45\right)-45\cdot54\)
\(=-45\cdot\left(12+34+54\right)\)
\(=-45\cdot100\)
\(=-4500\)
b) Ta có: \(43\cdot\left(57-33\right)+33\cdot\left(43-57\right)\)
\(=43\cdot57-43\cdot33+43\cdot33-33\cdot57\)
\(=43\cdot57-33\cdot57\)
\(=57\cdot\left(43-33\right)\)
\(=57\cdot10=570\)
\(3^{x-3}+2.3^{x-2}+3^{x-1}=144\)
\(\Rightarrow3^{x-1}.3^{-2}+3^{x-1}.3^{-1}.2+3^{x-1}=144\)
\(\Rightarrow3^{x-1}\left(3^{-2}+3^{-1}.2+1\right)=144\)
\(\Rightarrow3^{x-1}\left(\frac{1}{9}+\frac{2}{3}+1\right)=144\)
\(\Rightarrow\frac{16}{9}.3^{x-1}=144\)
\(\Rightarrow3^{x-1}=144:\frac{16}{9}\)
\(\Rightarrow3^{x-1}=81\)
\(\Rightarrow3^{x-1}=3^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)