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a; \(\dfrac{93}{17}\): \(x\) + (- \(\dfrac{21}{17}\)) : \(x\) + \(\dfrac{22}{7}\): \(\dfrac{22}{3}\) = \(\dfrac{5}{14}\)
\(\dfrac{94}{17}\) \(\times\) \(\dfrac{1}{x}\) - \(\dfrac{21}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)
\(\dfrac{72}{17}\) \(\times\) \(\dfrac{1}{x}\) + \(\dfrac{3}{7}\) = \(\dfrac{5}{14}\)
\(\dfrac{72}{17x}\) = \(\dfrac{5}{14}\) - \(\dfrac{3}{7}\)
\(\dfrac{72}{17x}\) = - \(\dfrac{1}{14}\)
17\(x\) = 72.(-14)
17\(x\) = - 1008
\(x\) = - 1008 : 17
\(x\) = - \(\dfrac{1008}{17}\)
Vậy \(x\) \(=-\dfrac{1008}{17}\)
b; - \(\dfrac{32}{27}\) - (3\(x\) - \(\dfrac{7}{9}\))3 = - \(\dfrac{24}{27}\)
- \(\dfrac{32}{27}\) + \(\dfrac{24}{27}\) = (3\(x\) - \(\dfrac{7}{9}\))3
(3\(x-\dfrac{7}{9}\))3 = - \(\dfrac{8}{27}\)
(3\(x-\dfrac{7}{9}\))3 = (- \(\dfrac{2}{3}\))3
3\(x-\dfrac{7}{9}\) = - \(\dfrac{2}{3}\)
3\(x\) = - \(\dfrac{2}{3}\) + \(\dfrac{7}{9}\)
3\(x\) = \(\dfrac{1}{9}\)
\(x\) = \(\dfrac{1}{9}\) : 3
\(x\) = \(\dfrac{1}{27}\)
Vậy \(x=\dfrac{1}{27}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
( x - 7 ) ( 2y + 3 ) = 32
<=> ( 2x - 14 ) y + 3x - 21 = 32
<=> ( 2x - 14) y + 3x - 32 - 21 = 0
<=> ( 2x - 14 ) y + 3x - 53 = 0
<=> ( 2x - 7) = 0
<=> 2x=2.7
<=> x = 7
<=> 2y + 3 = 0
<=> 2y = -3
<=> y = -1,5
Có \(2xy+3x-2y=20\)
\(\Rightarrow\left(2xy-2y\right)+3x=20\)
\(\Rightarrow2y\left(x-1\right)+3x=20\)
\(\Rightarrow2y\left(x-1\right)+3x-3=20-3\)
\(\Rightarrow2y\left(x-1\right)+3\left(x-1\right)=17\)
\(\Rightarrow\left(2y+3\right)\left(x-1\right)=17\)
\(\Rightarrow\hept{\begin{cases}2y+3\inƯ\left(17\right)\\x-1\inƯ\left(17\right)\end{cases}}\)
Ta có bảng giá trị sau:
2y+3 | 1 | 17 | -17 | -1 |
x-1 | 17 | 1 | -1 | -17 |
x | 18 | 2 | 0 | -16 |
y | -1 | 7 | -10 | -2 |
Vậy các cặp (x;y) thỏa mãn là (18;-1),(2;7),(0;-10);(-16;-2)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -6 (20-32) -(-85+19)
=-6 (-12)+85+19
=72+85+19
=176
b) -3x.68-68.7
=68.7-(-3x)
=68.7+3x
=476+3x
=479x
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 45 - 3x = 15
3x = 30
x = 10
b) 4x - 20 = 32
4x = 52
x = 13
c) 2x : 16 = 14
2x = 224
x = 112
d) 0 : 5x = 0
=> x thuộc Z
e) 3240 : 9x = 18
9x = 180
x = 20
a,45-3x=15
-3x=-30
x=10
b,4x-20=32
4x=52
x=13
c,2x:16=14
2x=224
x=112
d,0:5x=0
5x=0
x=0
e,3240:9x=18
9x=180
x=20
=.= hok tốt!!
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 45 - 3x = 15 b) 4x - 20 = 32 c) 2x : 16 = 14 d) 0 : 5x = 0
3x = 45 - 15 4x = 32 + 20 2x = 14 x 16 Vì 0 chia cho bất cứ số nào
3x = 30 4x = 52 2x = 224 cũng bằng 0 nên suy ra x thuộc Z
x = 30 : 3 x = 52 : 4 x = 224 : 2
x = 10 x = 13 x = 112
e) 3240 : 9x = 18 f) [ 1824 - ( 526 + 2x ) ] + 318 =1420 Câu g) tương tự như câu f)
9x = 3240 : 18 1824 - (526 + 2x) = 1420 - 318
9x = 180 1824 - (526 + 2x) = 1102
x = 180 : 90 526 + 2x = 1824 - 1102
x = 20 526 + 2x = 722
2x = 722 - 526
2x = 196
x = 196 : 2
x = 98
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11: Ta có: \(\left(x+3\right)^3=125\)
\(\Leftrightarrow x+3=5\)
hay x=2
12: Ta có: \(\left(2x\right)^4=16\)
\(\Leftrightarrow x^4=1\)
hay \(x\in\left\{1;-1\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,3x + 20 = -5x - (-36) => 3x + 20 = -5x + 36 => 8x = 16 => x=2
b,32 + x = 6 ( x +2 )=> 32 + x = 6x+12=>-5x=-20=>x=4
c,| x -2 | -3 = 5=>| x -2 | = 8 => x -2 = 8 hoặc x -2 = -8 => x=10 hoặc x=-6
a) 3x+5x=36-20 => 8x=16 => x =2 .
b) x+32=6x+12 => x-6x=12-32 => -5x=-20 => x=4
c) / x-2 / = 5+3 =8 => x-2=8 hoặc x-2=-8.
=> x=10 hoặc x=-6 .
![](https://rs.olm.vn/images/avt/0.png?1311)
d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)
\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)
hay \(x=\dfrac{25}{372}\)
Vậy: \(x=\dfrac{25}{372}\)
e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)
f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)
\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)
\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)
\(\Leftrightarrow3x=\dfrac{1}{9}\)
hay \(x=\dfrac{1}{27}\)
g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)
\(\Leftrightarrow\dfrac{4}{3}x=2\)
hay \(x=\dfrac{3}{2}\)
Vậy: \(x=\dfrac{3}{2}\)
h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)
Vậy ...
i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)
Vậy ...
Tìm x
\(3,75\left(3x:20+32\right)=120,45\)
\(3x:20+32=120,45:3,75\)
\(3x:20+32=32,12\)
\(3x:20=32,12-32\)
\(3x:20=0,12\)
\(3x=0,12.20\)
\(3x=2,4\)
\(x=2,4:3\)
\(x=0,8\)
Vậy \(x=0,8.\)
(3x:20+32)=120,45:3,75
(3x:20+32)=32,12
3x:20=32,12-32
3x:20=0,12
3x=0,12×20
3x=2,4
x=2,4:3
x=0,8
vậy x=0,8