K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

7 tháng 7 2021

Trả lời :

a) \(\frac{3}{7}-\frac{1}{2}x=\frac{5}{3}\)

\(\frac{1}{2}x=\frac{3}{7}-\frac{5}{3}\)

\(\frac{1}{2}x=-\frac{26}{21}\)

\(x=-\frac{26}{21}\div\frac{1}{2}\)

\(x=-\frac{52}{21}\)

Các câu khác làm tương tự

~HT~

a)  3/7 - 1/2x = 5/3

1/2 x = 3/7 - 5/ 3

 1/2 x = -26 / 21

 x= -26 / 21 : 1/2 

 x =-52 / 21 

b) -2/3x + 2 = 3/4

 -2 / 3 x = 3/4 - 2 

 -2/3 x = -5/4

x= -5/4 : (-2 /3 )

x = 15 /8 

c) 3/4 - 5/6x = 2 - 2/3

3/4 - 5/6 x = 4/3

5/6 x = 3 /4 - 4/3 

5/6 x = -7/ 12

 x= -7/12 : 5/6 

 x= -7 /10 

10 tháng 12 2021

\(2x-5=-11\Leftrightarrow x=-3\)

10 tháng 12 2021

\(\text{1/ (2x - 5) +17 =6}\\ 2x-5=6-17\\ 2x-5=-11\\ 2x=-11+5\\ x=-6:2\\ x=-3\)

18 tháng 1 2019

1)6x-8=3x+1

6x-3x=1+8

3x=9

x=3

Vậy x=3

2: 12-10x=25-30x

=>20x=13

=>x=13/20

3: \(3\left(2x+3\right)-2\left(4x-5\right)=10x+21\)

=>6x+9-8x+10=10x+21

=>10x+21=-2x+19

=>12x=-2

=>x=-1/6

4: \(\Leftrightarrow25x-15-6x+12=11-5x\)

=>19x-3=11-5x

=>24x=14

=>x=7/12

5: \(\Leftrightarrow8-12x-5+10x=4-6x\)

=>4-6x=-2x+3

=>-4x=-1

=>x=1/4

6: \(\Leftrightarrow32x-24-6+9x=13-40x\)

=>41x-30=13-40x

=>81x=43

=>x=43/81

7: \(\Leftrightarrow10x-5+20x=5x-11\)

=>30x-5=5x-11

=>25x=-6

=>x=-6/25

21 tháng 7 2018

a) ( 2x - 3 ) - ( x - 5 ) = ( x + 7 ) - ( x + 2 ) 

<=> 2x - 3 - x + 5 = x + 7 - x - 2

<=> x = 3

b)(7x-5)-(6x+4)=(2x+3)-(2x+1)

<=> 7x - 5 - 6x - 4 = 2x + 3 - 2x - 1

<=> x = 11

c)(9x-3)-(8x+5)=(3x+2)

<=> 9x - 3 - 8x - 5 = 3x + 2

<=> -2x = 10

<=> x = -5

d)(x+7)-(2x+3)=(3x+5)-(2x+4)

<=> x + 7 - 2x - 3 = 3x + 5 - 2x - 4

<=> -2x = -3

<=> x = 3/2

ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠᅠ ᅠ

14 tháng 9 2015

a) 12 ( 2x - 6 ) - 43= 53

12 ( 2x - 6 ) - 43= 125

12 ( 2x - 6 ) =125+43

12 ( 2x - 6 ) =168

2x - 6=168:12

2x - 6=14

2x=14+6

2x=20

x=20:2

x=10

b) 7 ( 25 - 3x ) = 34 - 25

 7 ( 25 - 3x ) = 49

25 - 3x =49:7

25 - 3x =7

3x=25-7

3x=18

x=18:3

x=6

c) ( 3x - 5 ) + 34 + 60 = 53

( 3x - 5 ) + 81 + 1 = 125

( 3x - 5 ) + 81=125-1

( 3x - 5 ) + 81=124

3x - 5=124-81

3x - 5=43

3x=43+5

3x=48

x=48:3

x=16

d) 3x + 2x ( 23 . 5 - 32 . 4 ) + 52 = 44

3x + 2x ( 8 . 5 - 9 . 4 ) + 25 = 256

3x + 2x.4 + 25 = 256

3x + 2x.4=256-25

3x + 2x.4=231

(3+2).x.4=231

5x.4=231

5x=231:4

5x=57,75

x=57,75:5

x=11,55

e) 720 : [ 41 - (2x - 5 ) ] = 23 .5

720 : [ 41 - ( 2x - 5 ) ] =40

41 - ( 2x - 5 )=720:40

41 - ( 2x - 5 )=18

 2x - 5=41-18

 2x - 5=23

2x=23+5

2x=28

x=28:2

x=14

Bài 1: 

a) Ta có: \(x\left(x^2-4\right)=0\)

\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)

Vậy: \(x\in\left\{0;2;-2\right\}\)

b) Ta có: \(\left(2x-3\right)+\left(-3x\right)-\left(x-5\right)=40\)

\(\Leftrightarrow2x-3-3x-x+5=40\)

\(\Leftrightarrow-2x+2=40\)

\(\Leftrightarrow-2x=38\)

hay x=-19

Vậy: x=-19

Bài 2: 

a) Ta có: \(-45\cdot12+34\cdot\left(-45\right)-45\cdot54\)

\(=-45\cdot\left(12+34+54\right)\)

\(=-45\cdot100\)

\(=-4500\)

b) Ta có: \(43\cdot\left(57-33\right)+33\cdot\left(43-57\right)\)

\(=43\cdot57-43\cdot33+43\cdot33-33\cdot57\)

\(=43\cdot57-33\cdot57\)

\(=57\cdot\left(43-33\right)\)

\(=57\cdot10=570\)

⇔(2 x ) 2+2.2 x .1+1 2=0 ... c ,(3 x −42−14(3 x −4)(6+3 x )+49(3 x +6)=16 ... ⇔9 x 224 x +16−126 x 2252 x +168 x +336+147 x +294=16.

https://olm.vn/hoi-dap/detail/192758180810.html

Giải:

a) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)  

     \(\dfrac{-5}{6}-x=\dfrac{1}{4}\)

               \(x=\dfrac{-5}{6}-\dfrac{1}{4}\) 

               \(x=\dfrac{-13}{12}\) 

b) \(2.\left(x-\dfrac{1}{3}\right)=\left(\dfrac{1}{3}\right)^2+\dfrac{5}{9}\) 

    \(2.\left(x-\dfrac{1}{3}\right)=\dfrac{1}{9}+\dfrac{5}{9}\) 

    \(2.\left(x-\dfrac{1}{3}\right)=\dfrac{2}{3}\)  

             \(x-\dfrac{1}{3}=\dfrac{2}{3}:2\) 

             \(x-\dfrac{1}{3}=\dfrac{1}{3}\) 

                    \(x=\dfrac{1}{3}+\dfrac{1}{3}\) 

                    \(x=\dfrac{2}{3}\) 

c) \(\left|2x-\dfrac{3}{4}\right|-\dfrac{3}{8}=\dfrac{1}{8}\) 

           \(\left|2x-\dfrac{3}{4}\right|=\dfrac{1}{8}+\dfrac{3}{8}\) 

            \(\left|2x-\dfrac{3}{4}\right|=\dfrac{1}{2}\) 

\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{3}{4}=\dfrac{1}{2}\\2x-\dfrac{3}{4}=\dfrac{-1}{2}\end{matrix}\right.\) 

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{8}\\x=\dfrac{1}{8}\end{matrix}\right.\) 

d) \(\dfrac{2}{3}x+\dfrac{1}{6}x=3\dfrac{5}{8}\) 

\(x.\left(\dfrac{2}{3}+\dfrac{1}{6}\right)=\dfrac{29}{8}\) 

            \(x.\dfrac{5}{6}=\dfrac{29}{8}\) 

                \(x=\dfrac{29}{8}:\dfrac{5}{6}\) 

                \(x=\dfrac{87}{20}\)