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Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
=> 1512 x X + 176 x X = 0
=> X x (1512 + 176) = 0
=> X = 0
\(\frac{22}{5}x\frac{25}{18}=\frac{550}{90}=\frac{55}{9}\)
\(\frac{9}{11}:2\frac{5}{2}x2\frac{3}{4}=\frac{9}{11}:\frac{9}{2}x\frac{11}{4}=\frac{9}{11}x\frac{2}{9}x\frac{11}{4}=\frac{1}{2}\)
\(10:\frac{35}{24}:\frac{36}{7}=10x\frac{24}{35}x\frac{7}{26}=\frac{10}{1}x\frac{24}{35}x\frac{7}{26}=\frac{24}{13}\)
10,77 x 9,8 + 5,23 x 9,8
= (10,77 + 5,23) x 9,8 = 16 x 9,8 = 156,8
1,26 x 3,6 : 0,28 - 6,2 = 4,536 : 0,28 - 6,2=
16,2 - 6,2 = 10
20/11 x 33/23 x 69/180 =
1/1 x 3/1 x 3/9 =
3/1 x 1/3 = 1
(Câu cuối trong fx không có phần gạch giữa {S} nên mình ghi tạm ngoài này nha bạn!)
x: 0,25 + X x 11 = 36
X x 4 + X x 11 = 36
X x ( 4+ 11 ) = 36
X x 15 = 36
X = 36 : 15 ( Tìm thừa số )
X = 2,4
X: 0,25 + X x 11 = 36
X x 4 + X x 11 = 36
X x (4 +11) = 36
X x 15 = 36
X = 36:15
X = 2,4
a) \(...\Rightarrow x.\left(2+5\right)=14\Rightarrow x.7=14\Rightarrow x=14:7=2\)
b) \(...\Rightarrow x.\left(9+1\right)=20\Rightarrow x.10=20\Rightarrow x=20:10=2\)
c) \(...\Rightarrow x.\left(\dfrac{2}{3}+\dfrac{1}{3}\right)=1999\Rightarrow x.\dfrac{3}{3}=1999\Rightarrow x=1999\)
d) \(...\Rightarrow11.x+22=5.x+40\Rightarrow11.x-5.x=40-22\Rightarrow6.x=18\Rightarrow x=18:6=3\)
e) \(...\Rightarrow11.x-66=4.x+11\Rightarrow11.x-4.x=11+66\Rightarrow7.x=77\Rightarrow x=77:7=11\)
f) \(...\Rightarrow\left(3.x-12\right):x=12-10\)
\(\Rightarrow3.x-12=2.x\)
\(\Rightarrow3.x-2.x=12\)
\(\Rightarrow x=12\)
g) \(...\Rightarrow\left(5.x+7\right):x=26-20\)
\(\Rightarrow5.x+7=6.x\)
\(\Rightarrow6.x-5.x=7\)
\(\Rightarrow x=7\)
h) \(...\Rightarrow x.\left(1999-1\right)=1999.\left(1997+1\right)\)
\(\Rightarrow x.1998=1999.1998\)
\(\Rightarrow x=1999.1998:1998\)
\(\Rightarrow x=1999\)
a, \(x\times\) 2 + \(x\times\) 5 = 14
\(x\) \(\times\) ( 2 + 5) = 14
\(x\) \(\times\) 7 = 14
\(x\) = 14: 7
\(x\) = 2
b, \(x\times9\) + \(x\)= 20
\(x\) \(\times\)( 9 + 1) = 20
\(x\) \(\times\) 10 = 20
\(x\) = 2
c, \(x\) : \(\dfrac{3}{2}\) + \(x\times\dfrac{1}{3}\) = 1999
\(x\times\) \(\dfrac{2}{3}\) + \(x\) \(\times\dfrac{1}{3}\) = 1999
\(x\times\) ( \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)) = 1999
\(x\) = 1999
d, 11\(\times\)(\(x+2\)) = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) + 22 = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 40 - 22
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 18
11 \(\times\) \(x\) - 5 \(\times\) \(x\) = 18
\(x\) \(\times\) ( 11 - 5) = 18
\(x\) \(\times\) 6 = 18
\(x\) = 3
=11*(36+84-20)=11*100=1100
\(=\left(36+84-20\right)\times11\)
\(=100\times11\)
= 1100