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x . y = 5
=> x = 1
=> y = 5
=> x = -1
=> y = -5
Vậy ( x ; y ) = ( 1 ; 5 ) hoặc ( -1 : - 5 )
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\(7\times2^{x+1}-3\times2^{x+1}=32\)
\(\Rightarrow2^{x+1}\left(7-3\right)=32\)
\(\Rightarrow2^{x+1}\times4=32\)
\(\Rightarrow2^{x+1}=32\div4\)
\(\Rightarrow2^{x+1}=8\)
\(\Rightarrow2^{x+1}=2^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=3-1\)
\(\Rightarrow x=2\)
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\(2^{x+3}-3.2^{x+1}=32\)
<=> 2^x.2^3-3.2^x.2=32
<=> 2^x.(2^3-3.2)=32
<=> 2^x.2=32
<=>2^x=16
<=>2^x=2^4
=>x=4
Vậy...
2x+3-3.2x+1=32
= 2x . 23 - 3. 21 .2x = 32
2x . 8 - 6 . 2x = 32
2x . (8 - 6 ) = 32
2x . 2 = 32
2x+1 = 32
vì 32 = 25 => x + 1=5
x = 5-1
x = 4
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\(2x+3-3.2x+1=32\)
\(2x.\left(1-3\right)=32-1-3\)
\(2x.\left(-2\right)=28\)
\(2x=-14\)
\(x=-7\)
Ta có: \(2x+3-3\cdot2\left(x+1\right)=32\)
\(\Leftrightarrow2x+3-6x-6=32\)
\(\Leftrightarrow-4x=35\)
\(\Rightarrow x=-\frac{35}{4}\)
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a.2.(x-11)-40=38 b.2015+{2016.[9-(11-8)^2]+7}
=2.(x-11)=38+40 = 2015+{2016.[9-3^2]+7}
=2.(x-11)=78 =2015+{2016.[9-9]+7}
=x-11=78:2 =2015+{2016.0+7}
=x-11=39 =2015+{0+7}
=x=39+11 =2015+7
=x=50 =2022
Nhớ k cho mik nha ^^
a)2.(x-11)=38+40=78
x-11=78:2=39
x=39+11
x=50
b)2022
c)sai đề rồi bạn ơi
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a: \(x^2\cdot x^3=32\)
\(\Leftrightarrow x^5=32\)
hay x=2
#)Thắc mắc :
Bạn ghi rõ giúp mình : 3 .2 là 3,2 hay 3 x 2 vậy bạn ???
32% . x + x = 3,2
=> x . (32% + 1) = 3,2
=> x . 33/25 = 3,2
=> x = 3,2 : 33/25
=> x = 80/33