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c: \(=\dfrac{3}{2}\cdot1-1-20=\dfrac{3}{2}-21=\dfrac{-39}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}-\dfrac{32}{17}+\dfrac{2}{3}\)
\(=\left(\dfrac{15}{34}+\dfrac{19}{34}\right)+\dfrac{7}{21}+\dfrac{-32}{17}+\dfrac{2}{3}\)
\(=1+\dfrac{1}{3}+\dfrac{-32}{17}+\dfrac{2}{3}\)
\(=1+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\dfrac{-32}{17}\)
\(=1+1+\dfrac{-32}{17}\)
\(2+\dfrac{-32}{17}=\dfrac{2}{17}\)
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c: \(=\dfrac{3}{2}-1-21=\dfrac{3}{2}-21=\dfrac{-39}{2}\)
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3x-21/3+4x-32/2 = 5x-37/4 +9x-33/6
7x+(-21/3-32/2) = 14x+(-37/4 - 33/6 )
7x+(-42/6-96/6) = 14x+ (-111/12 - 66/12)
7x+(-138/6) =14x + (-177/12)
7x - 14x =138/6 +(-177/12)
-7x = 276/12+ (-177/12)
-7x = 99/12
-x = 23/28
x = -23/28
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Ta có : \(32^{17}+16^{21}-2^{82}=\left(2^5\right)^{17}+\left(2^4\right)^{21}-2^{82}=2^{85}+2^{84}-2^{82}\)
\(=2^{80}.2^5+2^{80}.2^4-2^{80}.2^2=2^{80}.\left(2^5+2^4-2^2\right)=2^{80}.44⋮44\)
Vậy \(32^{17}+16^{21}-2^{82}⋮44\left(đpcm\right)\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
(32+21)2
= 53 . 2
= 106
-HT-
( 32 + 21 )2
=53 . 2
=106
chúc ban hok tốt !!