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`1)1/2:2/3 .... 2/3 : 1/2`
`=>1/2xx3/2 .... 2/3xx2`
`=>3/4 .... 4/3`
Vì `3/4 < 1` và `4/3>1`
`=>3/4<4/3`
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`4/7:2/5 ... 4/7 : 3/5`
`=>4/7xx5/2....4/7xx5/3`
`=>20/14...20/21`
`=>10/7...20/21`
Vì `10/7>1` và `20/21<1`
`=>10/7>20/21`
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`4/15:4/7....2/5xx10/3`
`=>4/15xx7/4...20/15`
`=>7/15...20/15`
Vì `7<20` nên `7/15<20/15`
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`5/6...15/18-11/18`
`=>5/6...4/18`
Ta có : MSC : `18`
`5/6 = 15/18`
Vì `15>4` nên `5/6 > 4/18`
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( \(\dfrac{2}{15}\) - \(\dfrac{1}{20}\) + \(\dfrac{3}{15}\) - \(\dfrac{9}{28}\) + \(\dfrac{2}{3}\)) : \(\dfrac{3}{4}\)
= { (\(\dfrac{2}{15}\) + \(\dfrac{3}{15}\)) + \(\dfrac{2}{3}\) - (\(\dfrac{1}{20}\) + \(\dfrac{9}{28}\))} : \(\dfrac{3}{4}\)
= { \(\dfrac{1}{3}\) + \(\dfrac{2}{3}\) - \(\dfrac{13}{35}\)) : \(\dfrac{3}{4}\)
= ( 1 - \(\dfrac{13}{35}\)): \(\dfrac{3}{4}\)
= \(\dfrac{22}{35}\) : \(\dfrac{3}{4}\)
= \(\dfrac{88}{105}\)
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\(\dfrac{8}{15}\times\dfrac{11}{2}+\dfrac{7}{15}\times\dfrac{11}{2}=\dfrac{11}{2}\left(\dfrac{8}{15}+\dfrac{7}{15}\right)=\dfrac{11}{2}\times\dfrac{15}{15}=\dfrac{11}{2}\times1=\dfrac{11}{2}\)
\(\dfrac{8}{12}+\dfrac{30}{12}-\dfrac{9}{12}=\dfrac{19}{12}\)
\(\dfrac{24}{30}-\dfrac{15}{30}+\dfrac{10}{30}=\dfrac{19}{30}\)
`8 / 15 : 2 / 11 + 7 / 15 : 2 / 11`
`= ( 8 / 15 + 7 / 15 ) : 2 / 11`
`= 15 / 15 xx 11 / 2`
`= 1 xx 11 / 2 = 11 / 2`
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`2 / 3 + 5 / 2 - 3 / 4`
`= 8 / 12 + 30 / 12 - 9 / 12`
`= 29 / 12`
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`4 / 5 - 1 / 2 + 1 / 3`
`= 24 / 30 - 15 / 30 + 10 / 30`
`= 19 / 30`
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7/15+18/15 = 25/15 = 5/3 5/4+17/12= 15/12 + 17/12 = 32/12 = 8/3 1/2+1/6+2/3 = 3/6 + 1/6 + 4/6 = 8/6 = 4/3 2+1/3 = 7/3
\(\dfrac{7}{15}+\dfrac{8}{15}=1\)
\(\dfrac{5}{4}+\dfrac{17}{12}=\dfrac{15}{12}+\dfrac{17}{12}=\dfrac{32}{12}=\dfrac{8}{3}\)
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{2}{3}=\dfrac{3}{6}+\dfrac{1}{6}+\dfrac{4}{6}=\dfrac{8}{6}=\dfrac{4}{3}\)
\(2+\dfrac{1}{3}=\dfrac{6}{3}+\dfrac{1}{3}=\dfrac{7}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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a)
Ta có : ( 1 + 2 + 3 + ... + 99)
Số số hạng là: ( 99 - 1 ) : 1 + 1 = 100
Tổng là: ( 99 + 1 ) x 100 : 2 = 5000
=> 5000 x ( 13 - 12 - 1 ) x 15
=> 5000 x 10 x 15
=> 50000 x 15
=> 750000
Ko muốn vt nx :))
\(\dfrac{2}{3}+\dfrac{1}{3}+15=16\)
\(\left(\frac{2}{3}+\frac{1}{3}\right)15\)
\(=\)\(\frac{3}{3}+15\)
\(=1+15\)
\(=16\)