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a) 24 + 17 + 26 = (24 + 26) + 17
= 50 + 17
= 67
b) 80 + 310 + 120 + 90 = (80 + 120) + (310 + 90)
= 200 + 400
= 600
c) 34 + 140 + 60 + 16 = (34 + 16) + (140 + 60)
= 50 + 200
= 250
\(G=\dfrac{9}{8}+\dfrac{23}{24}+\dfrac{1}{8}+\dfrac{17}{24}+\dfrac{13}{8}+\dfrac{19}{24}\\ \Rightarrow G=\left(\dfrac{9}{8}+\dfrac{1}{8}+\dfrac{13}{8}\right)+\left(\dfrac{23}{24}+\dfrac{17}{24}+\dfrac{19}{24}\right)\\ \Rightarrow G=\dfrac{23}{8}+\dfrac{59}{24}\\ \Rightarrow G=\dfrac{69}{24}+\dfrac{59}{24}\\ \Rightarrow G=\dfrac{128}{24}\\ \Rightarrow G=\dfrac{16}{3}\)
\(=\left(\dfrac{9}{8}+\dfrac{1}{8}+\dfrac{13}{8}\right)+\left(\dfrac{23}{24}+\dfrac{17}{24}+\dfrac{19}{24}\right)\)
\(=\dfrac{23}{8}+\dfrac{59}{24}\)
\(=\dfrac{16}{3}\)
\(a)\dfrac{5}{7}\times\dfrac{7}{15}\\ =\dfrac{5\times7}{7\times15}\\ =\dfrac{35}{105}=\dfrac{1}{3}\\ b)\dfrac{8}{21}\times3\\ =\dfrac{8\times3}{21}\\ =\dfrac{24}{21}=\dfrac{8}{7}\\ c)\dfrac{24}{17}:\dfrac{9}{17}\\ =\dfrac{24}{17}\times\dfrac{17}{9}\\ =\dfrac{24\times17}{17\times9}\\ =\dfrac{408}{153}=\dfrac{8}{3}\\ d)\dfrac{36}{5}:9\\ =\dfrac{36}{5}\times\dfrac{1}{9}\\ =\dfrac{36\times1}{5\times9}\\ =\dfrac{36}{45}=\dfrac{4}{5}\)
a) \(\dfrac{5}{7}\times\dfrac{7}{15}=\dfrac{5\times7}{7\times15}=\dfrac{35}{105}=\dfrac{1}{3}\)
b) \(\dfrac{8}{21}\times3=\dfrac{8\times3}{21}=\dfrac{24}{21}=\dfrac{8}{7}\)
c) \(\dfrac{24}{17}:\dfrac{9}{17}=\dfrac{24}{17}\times\dfrac{17}{9}=\dfrac{24\times17}{17\times9}=\dfrac{24}{9}=\dfrac{8}{3}\)
d) \(\dfrac{36}{5}:9=\dfrac{36}{5}\times\dfrac{1}{9}=\dfrac{36}{5\times9}=\dfrac{36}{45}=\dfrac{4}{5}\)
1200 : 24 -( 17 - x )=36
50 -( 17 - x )=36
17 - x = 50 - 36
17 - x = 14
x = 17 - 14
x = 3
1200 : 24 -( 17 - x )=36
50 -( 17 - x )=36
17 - x = 50 - 36
17 - x = 14
x = 17 - 14
x = 3
b. \(\dfrac{4.2.3.5.2.6.2.5.3}{4.3.4.5.6.4.5.6}=\dfrac{1}{4}\)
c. \(\dfrac{17.2.101.2005}{17.2.101.2.2005}=\dfrac{1}{2}\)
d. \(\dfrac{2.3.4.2.11.13.17}{3.11.4.4.17.13.2}=\dfrac{1}{2}\)
a)\(\dfrac{4\times6\times10\times12\times15}{4\times12\times5\times24\times30}=\dfrac{2}{2\times2\times2}=\dfrac{2}{8}=\dfrac{1}{4}\)
b)\(\dfrac{34\times101\times2005}{17\times202\times4010}=\dfrac{2}{2\times2}=\dfrac{2}{4}=\dfrac{1}{2}\)
c)\(\dfrac{6\times8\times11\times13\times17}{33\times16\times17\times26}=\dfrac{6}{3\times2\times2}=\dfrac{1}{2}\)
17 + 17 - 24
= 34 - 24
= 10
TL:
17+17-24
= 34 - 24
= 10
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