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\(\frac{x+22}{11}+\frac{x+23}{12}=\frac{x+24}{13}+\frac{x+25}{14}\)
\(\Leftrightarrow\left(\frac{x+22}{11}+1\right)+\left(\frac{x+23}{12}+1\right)=\left(\frac{x+24}{13}+1\right)+\left(\frac{x+25}{14}+1\right)\)
\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}=\frac{x+37}{13}+\frac{x+39}{14}\)
\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}-\frac{x+37}{13}-\frac{x+39}{14}=0\)
\(\Leftrightarrow\frac{2184\cdot\left(x+33\right)+2002\cdot\left(x+35\right)-1848\cdot\left(x+37\right)-1716\cdot\left(x+39\right)}{24024}=0\)
\(\Leftrightarrow2184x+72072+2002x+70070-1848x-68376-1716x-66924=0\)
\(\Leftrightarrow622x+6842=0\)
\(\Leftrightarrow x=-11\)
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9/17.x+268/17.x-345/17.x=16
(9/17+268/17-345/17).x=16
-4.x=16
x=16:-4
x=-4
\(\dfrac{9}{17}x+15\dfrac{13}{17}x-20\dfrac{5}{17}x=16\)
\(\left(\dfrac{9}{17}+15\dfrac{13}{17}-20\dfrac{5}{17}\right)x=16\)
\(\left(\dfrac{9}{17}+\dfrac{268}{17}-\dfrac{345}{17}\right)x=16\)
\(x=16:\left(\dfrac{9}{17}+\dfrac{268}{17}-\dfrac{345}{17}\right)\)
\(x=-4\)
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3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
3/14 × 5/17 + 11/14 × 5/17 + 12/17 × 5/16 + 12/17 × 11/16
= 5/17 × ( 3/14 + 11/14) + 12/17 × ( 5/16 + 11/16)
= 5/17 × 1 + 12/17 × 1
= 5/17 + 12/17
= 1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(17-\left\{-x-\left[-x-\left(-x\right)\right]\right\}=-16\\ \Rightarrow17-\left(-x\right)=-16\\ \Rightarrow17+x=-16\\ \Rightarrow x=-16-17=-33\)
Vậy x = -33
Ta có: \(17-\left\{-x-\left[-x-\left(-x\right)\right]\right\}=-16\)
\(\Leftrightarrow17-\left[-x-\left(-x+x\right)\right]=-16\)
\(\Leftrightarrow17+x=-16\)
hay x=-33
Vậy: x=-33
![](https://rs.olm.vn/images/avt/0.png?1311)
`17-{-x-[-x-(-x)]}=-16`
`=>17-[x-(-x+x)]=-16`
`=>17-(x-0)=-16`
`=>17-x=-16`
`=>x=17+16`
`=>x=33`
Vậy `x=33`
\(17-\left\{-x\left[-x-\left(-x\right)\right]\right\}=-16\\ \Rightarrow17-\left[-x.0\right]=-16\\ \Leftrightarrow17=-16\left(\text{vô lý}\right)\)
Vậy \(x\in\varnothing\)