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a, = 15 x (3+7) + 15 = 15 x 10 + 15 = 150 + 15 = 165
b, = 24 x 18 - 24 x 8 + 24 = 24 x (18-8) + 24 = 24 x 10 + 24 = 240 + 24 = 264
k mk nha
a,15*3+15*7+15
=15*(3+7)
=15*10
=150
b,24*18-24*7
=24*(18-7)
=24*11
=264
tk cho mk nha^-^
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\(\dfrac{5}{7}\)>\(\dfrac{6}{21}\)
\(\dfrac{18}{24}\)>\(\dfrac{15}{25}\)
\(\dfrac{12}{13}\)=\(\dfrac{1212}{1313}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 9/7 và 10/14
10/14 để nguyên
(nhân cả tử và mẫu với 2) 9/7 = (9x2)/(7x2)=18/14
so s.ánh 18/14 và 10/14( vì 18/14 > 10/14 nên
9/7 > 10/14
Cách 2 :
Rút gọn 10/14 = 5/7
so sánh 9/7 với 5/7 , vì 9 > 5 nên 9/7 > 5/7
Vậy 9/7 > 10/14
B ) 15/24 và 18/16
Cách 1 : Rút gọn 15/24 và 18/16
15/24 = 5/8 , 18/16 = 9/8
vì 5/8 < 9/8 nên 15/24 < 18/16
Cách 2 : Quy đồng 2 phân số có mẫu chung là 48
15/24 = 15 x 2 /24 x 2= 30/48
18/16 = 18 x 3 / 16 x 3 = 54/48
vid 10/48<54/48 nên 15/24 < 18/16
tick điiiii , tui bỏ ăn cơm để trình bày cho đó
a)C1:Ta có:\(\frac{9}{7}\)=\(\frac{18}{14}\)
=>\(\frac{9}{7}\)> \(\frac{10}{14}\)vì \(\frac{18}{14}\)>\(\frac{10}{14}\)
C2:Ta có\(\frac{9}{7}\)> 1 ; \(\frac{14}{10}\)< 1
=>\(\frac{9}{7}\)> \(\frac{10}{14}\)
b)C1:Ta có\(\frac{15}{24}\)=\(\frac{30}{48}\) ; \(\frac{18}{16}\)= \(\frac{54}{48}\)
=>\(\frac{15}{24}\)<\(\frac{18}{16}\)vì \(\frac{30}{48}\)<\(\frac{54}{48}\)
C2:Ta có \(\frac{15}{24}\) < 1 ; \(\frac{18}{16}\)> 1
=>\(\frac{15}{24}\)>\(\frac{18}{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
4 : 9 = \(\dfrac{4}{9}\) 8 : 11 =\(\dfrac{8}{11}\) 7 : 15 =\(\dfrac{7}{15}\)
15 : 5 = \(\dfrac{15}{5}=\dfrac{3}{1}\) 63 : 21 =\(\dfrac{63}{21}\) 45 : 9 =\(\dfrac{45}{9}=\dfrac{5}{1}\)
6 : 18 = \(\dfrac{6}{18}=\dfrac{1}{3}\) 144 : 24 =\(\dfrac{244}{24}\) 7 =\(\dfrac{7}{1}\)
15 = \(\dfrac{15}{1}\) 10 = \(\dfrac{10}{1}\) 0 =\(\dfrac{0}{1}\)
\(4:9=\dfrac{4}{9};15:5=\dfrac{15}{5}=3;6:18=\dfrac{6}{18}=\dfrac{1}{3}\\ 15=\dfrac{15}{1};8:11=\dfrac{8}{11};63:21=\dfrac{63}{21}=3;144:24=\dfrac{144}{24};10=\dfrac{10}{1}\\ 7:15=\dfrac{7}{15};45:9=\dfrac{45}{9}=5;7=\dfrac{7}{1};0=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ᵃ, ᵗᵃ ʳᵘ́ᵗ ᵍᵒ̣ⁿ :\(\dfrac{18}{24}=\dfrac{3}{4}\) ;
ᵗᵃ ʳᵘ́ᵗ ᵍᵒ̣ⁿ :\(\dfrac{15}{25}=\dfrac{3}{5}\)
Vì \(\dfrac{3}{4}>\dfrac{3}{5}\\ \Rightarrow\dfrac{18}{24}>\dfrac{15}{25}\)
ᵇ, ᵗᵃ ʳᵘ́ᵗ ᵍᵒ̣ⁿ :\(\dfrac{21}{15}=\dfrac{7}{5}\\ \dfrac{28}{24}=\dfrac{7}{6}\)
Vì \(\dfrac{7}{5}>\dfrac{7}{6}\\ \Rightarrow\dfrac{21}{15}>\dfrac{28}{24}\)
a, \(\dfrac{18}{24}\) = \(\dfrac{3}{4}\) \(\dfrac{15}{25}\) = \(\dfrac{3}{5}\)
\(\dfrac{3}{4}\) > \(\dfrac{3}{5}\) vậy \(\dfrac{18}{24}\) > \(\dfrac{15}{25}\)
b, \(\dfrac{21}{15}\) = \(\dfrac{7}{5}\) \(\dfrac{28}{24}\) = \(\dfrac{7}{6}\)
\(\dfrac{7}{5}\) > \(\dfrac{7}{6}\) vậy \(\dfrac{21}{15}\) > \(\dfrac{28}{24}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a: \(=\dfrac{21}{7}\cdot\dfrac{15}{45}\cdot\dfrac{9}{18}=3\cdot\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{1}{2}\)
b: \(=\dfrac{11}{33}\cdot\dfrac{24}{8\cdot12}\cdot\dfrac{27}{9}=\dfrac{24}{96}=\dfrac{1}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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27/15 + 6/8 =51/20
19/24 + 7/18 = 85/72
2/9 - 1/6 = 1/18
8/15 -1/3 = 1/5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{5}{7}=\dfrac{15}{21};\dfrac{6}{8}=\dfrac{3}{4};\dfrac{8}{9}=\dfrac{16}{18};\dfrac{12}{16}=\dfrac{18}{24}\)
\(\dfrac{5}{7}=\dfrac{15}{21};\dfrac{6}{8}=\dfrac{18}{24};\dfrac{8}{9}=\dfrac{16}{18};\dfrac{3}{4}=\dfrac{12}{16}\)
so sánh à bn
\(\dfrac{15}{24}\) > \(\dfrac{12}{24}=\dfrac{1}{2}\)
\(\dfrac{7}{18}< \dfrac{9}{18}=\dfrac{1}{2}\)
\(\dfrac{15}{24}\) > \(\dfrac{7}{18}\)