![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(x+\frac{2}{3}\right)^3=\frac{1}{8}\)
\(\Rightarrow x+\frac{2}{3}=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{2}{3}\)
\(x=\frac{-1}{6}\)
b) 52x-1-125 = 0
52x-1 = 0+125
52x-1 = 125
<=> 52x-1 = 53
=> 2x-1=3
=> x = 2
c) \(\frac{8^1}{3^{2x+1}}=3\)
\(\Rightarrow8=3.3^{2x+1}=3^{2x+1+1}=3^{2x+2}\)
\(\Rightarrow8\ne3^{2x+2}\)
=> x vô nghiệm
a, \(\left(\frac{x+2}{3}\right)^3=\frac{1}{8}\)\(\Rightarrow\left(\frac{x+2}{3}\right)^3=\left(\frac{1}{2}\right)^3\)
\(\Rightarrow\frac{x+2}{3}=\frac{1}{2}\)\(\Rightarrow\left(x+2\right).2=3.1\)\(\Rightarrow x+2=\frac{3}{2}\)\(\Rightarrow x=-\frac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\Leftrightarrow4^{x-5}\cdot17=68\)
=>4^x-5=4
=>x-5=1
=>x=6
b: \(\Leftrightarrow\dfrac{1}{3}:\left|2x-1\right|=\dfrac{1}{3}+\dfrac{2}{3}=1\)
=>|2x-1|=1/3
=>2x-1=1/3 hoặc 2x-1=-1/3
=>x=2/3 hoặc x=1/3
c: =>|2x-2|=|3x+15|
=>3x+15=2x-2 hoặc 3x+15=-2x+2
=>x=-17 hoặc x=-13/5
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
\(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}=\frac{9}{15}-\frac{10}{15}=\frac{-1}{15}\)
\(x=\frac{-1}{15}.\frac{1}{3}\)
\(x=\frac{-1}{45}\)
Vậy x = \(\frac{-1}{45}\)
c) \(\left|2x-1\right|+1=4\)
\(\left|2x-1\right|=4-1=3\)
2x-1 = 3 ; -3
TH1: 2.x - 1 = 3
2.x = 3 + 1 = 4
x = 4 : 2 = 2
TH2: 2.x - 1 = -3
2.x = -3 + 1 = -2
x = -2 : 2 = -1
Vậy x \(\in\){ 2 ; -1 }
Ngại làm ấn máy ==
![](https://rs.olm.vn/images/avt/0.png?1311)
(2x-1)\(^3\)=-125
(2x-1)\(^3\)= - 5\(^3\)
2x - 1 = -5
2x = -5+1
2x =-4
x = -4:2
x = -2
![](https://rs.olm.vn/images/avt/0.png?1311)
1)
a) \(|2x+1|-3=4x\)
\(\Leftrightarrow|2x+1|=4x+3\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=4x+3\\2x+1=-4x-3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-4x=3-1\\2x+4x=-3-1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}-2x=2\\6x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-1\\x=\frac{-2}{3}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
MK chỉ làm câu b và c thôi nha
b)2x+|x-3|=6
TH1:2x+x-3=6
3x-3=6
3x=9
x=3
TH2:2x+-(x-3)=6
2x-x+3=6
x+3=6
x=3
Vậy x=3
c)3x-1=|2x-1|
TH1:3x-1=2x-1
3x-1-2x+1=0
x=0
TH2:3x-1=-(2x-1)
3x-1=1+2x
3x-1-1-2x=0
x-2=0
x=2
Vậy x=0;2
![](https://rs.olm.vn/images/avt/0.png?1311)
(2x+1)3=125/27
(2x+1)3=(5/3)3
2x+1=5/3
2x=5/3-1
2x=2/3
x=1/3
sai thôi
(2x + 1)3 = 125/27
=> 2x + 1 = 5/3
=> 2x = 5/3 -1
=> 2x = 2/3
=> x = 1/3
Ta có \(\left(-\frac{1}{3}+2x\right)^3=\frac{-1}{125}\)
\(\Rightarrow\left(-\frac{1}{3}+2x\right)^3=-\left(\frac{1}{5}\right)^3\)
\(\Rightarrow2x=-\frac{1}{5}+\frac{1}{3}\)
\(\Rightarrow2x=\frac{2}{15}\)
\(\Rightarrow x=\frac{1}{15}\)
\(\Rightarrow2x=-\frac{1}{5}+\frac{1}{3}\)