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1/4 + 1/3 : (2x - 1) = -5
=> 1/3 : (2x - 1) = -21/4
=> 2x - 1 = -63/4
=> 2x = -59/4
=> x = -59/8
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\frac{1}{3}:\left(2x-1\right)=\left(-5\right)-\frac{1}{4}\)
\(\frac{1}{3}:\left(2x-1\right)=\frac{-21}{4}\)
\(2x-1=\frac{1}{3}:\frac{-21}{4}\)
\(2x-1=\frac{-4}{63}\)
\(2x=\frac{-4}{63}+1\)
\(2x=\frac{59}{63}\)
\(x=\frac{59}{63}:2\)
\(x=\frac{59}{126}\)
(1-1/1.2)+(1-1/2*3)+......+(1-1/2015*2016)
=(0/1*2)+(0+2*3)+..........+(0/2015*2016)
=0
tui nghĩ cái đề phải như thế này \(\left(1-\frac{1}{1.2}\right)+\left(1-\frac{1}{2.3}\right)+\left(1-\frac{1}{3.4}\right)+...+\left(1-\frac{1}{2015.2016}\right)\)
\(B=2+2^2+2^3+...+2^{2016}\)
\(2B=2^2+2^3+...+2^{2017}\)
\(B=2^{2017}-2\)
các ý khác tương tự
ý C nhân vs 3
D 4
E 5
3C = 3(1+3+3^2+.......+3^2017)
= 3+3^2+3^3+......+3^2018
3C - C = (3+3^2+3^3+......+3^2018) - (1+3+3^2+......+3^2017)
= 3^2018 - 1
=> C = (3^2018 - 1) : 2
còn lại tự làm nhé
\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right)......\left(1+\frac{1}{2016.2018}\right)\)
\(=\left(\frac{1.3}{1.3}+\frac{1}{1.3}\right).\left(\frac{2.4}{2.4}+\frac{1}{2.4}\right).....\left(\frac{2016.2018}{2016.2018}+\frac{1}{2016.2018}\right)\)
\(=\left(\frac{1.3+1}{1.3}\right).\left(\frac{2.4+1}{2.4}\right).....\left(\frac{2016.2018+1}{2016.2018}\right)\)
\(=\frac{4}{1.3}.\frac{9}{2.4}.....\frac{4068289}{2016.2018}=\frac{2^2}{1.3}.\frac{3^2}{2.4}....\frac{2017^2}{2016.2018}\)
\(=\frac{2^2.3^2.....2017^2}{1.3.2.4.....2016.2018}=\frac{2.2.3.3.4.4...2017.2017}{1.3.2.4.....2016.2018}=\frac{\left(2.3.4.....2017\right).\left(2.3.4..2017\right)}{\left(1.2....2016\right).\left(3.4....2018\right)}\)
\(=\frac{2017.2}{1.2018}=\frac{4034}{2018}\)
thank you bạn nha