Question

[nguyễn thị lan anh]

(11¹²+2015²⁰¹⁶) chia hết cho 2

Answer 1

[.]

Nếu đề bài là: Chứng minh rằng.

Ta có:11¹²=\(\overline{...1}\)

          2015²⁰¹⁶=\(\overline{...5}\)

Mà \(\left(\overline{...1}\right)\)+\(\left(\overline{...5}\right)\)=\(\overline{...6}\)\(⋮\)2

\(\Rightarrow\)11¹²+2015²⁰¹⁶\(⋮\)2

Vậy 11¹²+2015²⁰¹⁶\(⋮\)2.

Answer 2

[Me]

                                                      Bài giải

\(11^{12}+2015^{2016}=\overline{\left(...1\right)}^{12}+\overline{\left(...5\right)}^{2016}=\overline{\left(...1\right)}+\overline{\left(...5\right)}=\overline{\left(...6\right)}\text{ }⋮\text{ }2\)

\(\Rightarrow\text{ ĐPCM}\)