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10 + 10 + 10 + 10 + 10
= 20 + 10 + 10 + 10
= 30 + 10 + 10
= 40 + 10
= 50
10 + 10 + 10 + 10 + 10
= 10 . 5
= 50
90 + 90 + 90 + 90 + 90
= 180 + 90 + 90 + 90
= 270 + 90 + 90
= 360 + 90
= 450
90 + 90 + 90 + 90 + 90
= 90 . 5
= 450
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1,1020và 9010
ta có:+,1020=(102)10=10010
+,9010=9010
vì 10010>9010=>1020>9010
2,(1/16)10 và (1/2)50
ta có:+, (1/16)10=(1/16)10
+,(1/2)50=(1/25)10=(1/32)10
vì (1/16)10>(1/32)10=>(1/16)10>(1/2)50
k mik nhé
\(a,\) \(10^{20}=10^{10+10}=10^{10}.10^{10}\)
\(90^{10}=9^{10}.10^{10}\)
Vì \(10^{10}.10^{10}>9^{10}.10^{10}\)
\(\Rightarrow10^{20}>90^{10}\)
Vậy \(10^{20}>90^{10}\)
\(b,\)\(\left(\frac{1}{16}\right)^{10}=\frac{1^{10}}{16^{10}}=\frac{1}{\left(4^2\right)^{10}}=\frac{1}{4^{20}}\)
\(\left(\frac{1}{2}\right)^{50}=\frac{1^{50}}{2^{50}}=\frac{1}{\left(2^2\right)^{25}}=\frac{1}{4^{25}}\)
Vì \(\frac{1}{4^{20}}>\frac{1}{4^{25}}\)
\(\Rightarrow\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)
Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)
~~~~~~~~~~Hok tốt~~~~~~~~~~~
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 1020 = 102.10 = (102)10 = 10010
Vì 10 > 0 và 100 > 90 nên 10010 > 9010 hay 1020 > 9010 .
Vậy 1020 > 9010
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^2-\dfrac{1}{10}=\dfrac{23}{90}\)
\(x^2-\dfrac{9}{90}=\dfrac{23}{90}\)
\(x^2=\dfrac{16}{45}\)
\(\Leftrightarrow x=\sqrt{\dfrac{16}{45}}\)
\(\Leftrightarrow x=-\sqrt{\dfrac{16}{45}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
4x-10+3x-5=90
(4x+3x)+(-10-5)=90
7x-15=90
7x=90+15
7x=105
x=105/7
x=15
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a) \(10^n+1-6\cdot10^n=\left(1-6\right)10^n+1=-5\cdot10^n+1\)
b) \(90\cdot10^n-10^2-2+10^n+1=\left(90-1+1\right)\cdot10^n-2+1=90\cdot10^n-1\)
c) \(2,5\cdot56^n-3=\frac{5}{2}\cdot56^n-3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{\left(x+3\right)}{7}+\dfrac{\left(x+4\right)}{6}+\dfrac{\left(x+90\right)}{10}+3=0\\ \Leftrightarrow\dfrac{60\left(x+3\right)}{420}+\dfrac{70\left(x+4\right)}{420}+\dfrac{42\left(x+90\right)}{420}+\dfrac{1260}{420}=0\\ \Leftrightarrow60x+180+70x+280+42x+3780+1260=0\\ \Leftrightarrow172x=-5500\\ \Leftrightarrow x=-\dfrac{1375}{43}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Theo định lí Pytago ta có
\(BC^2=AB^2+AC^2\\ AB^2=BC^2-AC^2=\sqrt{10^2-8^2}\\ =\sqrt{100-64}=6\)
Tổng 2 số trên là:
10 + 90 = 100
Đáp số: 100
=100
giúp tớ nhé
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