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\(=10^3:5^3+10^4:5^3+125^2:5^3\)
\(=2^3+2^3\times10+125\)
\(=8+80+125\)
\(=88+125\)
\(=213\)
( 10 mũ 3 + 10 mũ 4 + 125 mũ 2 ) : 5 mũ 3
= (1000 + 10000 + 5 mũ 3 .2 ) : 5 mũ 3
= ( 1000 + 10000 + 5 mũ 6 ) ; 5 Mũ 3
= ( 11000 + 15625 ) : 125
= 26625 : 125
= 213
B={[5^10. 7^3 - 25^2 . 49^2] : [(125 . 7)^3+5^9 . 14^3]} - {[2^12-4^6 . 9^2] : [(2^2.3)^6+8^4 . 3^5]
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Sửa đề: \(5^9\cdot49^2\)
\(=\dfrac{5^{10}\cdot7^3-5^9\cdot7^4}{5^9\cdot7^3+5^9\cdot14^3}-\dfrac{2^{12}-2^{12}\cdot3^4}{2^{12}\cdot3^6+2^{12}\cdot3^5}\)
\(=\dfrac{5^9\cdot7^3\left(5-7\right)}{5^9\cdot7^3\left(1+8\right)}-\dfrac{2^{12}\left(1-3^4\right)}{2^{12}\left(3^6+3^5\right)}=\dfrac{-2}{9}+\dfrac{80}{972}\)
=-34/243
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a: \(\Leftrightarrow4^{x-5}\cdot17=68\)
=>4^x-5=4
=>x-5=1
=>x=6
b: \(\Leftrightarrow\dfrac{1}{3}:\left|2x-1\right|=\dfrac{1}{3}+\dfrac{2}{3}=1\)
=>|2x-1|=1/3
=>2x-1=1/3 hoặc 2x-1=-1/3
=>x=2/3 hoặc x=1/3
c: =>|2x-2|=|3x+15|
=>3x+15=2x-2 hoặc 3x+15=-2x+2
=>x=-17 hoặc x=-13/5
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\(=\dfrac{10+5+100+125}{216+3+36+27}\cdot\dfrac{7}{125}=\dfrac{240}{282}\cdot\dfrac{7}{125}=\dfrac{56}{1175}\)
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(103 + 104 + 1252) : 53
= (23.53 + 24.54 + 56) : 53
= 53.(23 + 24.5 + 53) : 53
= 23 + 24.5 + 53
= 8 + 16.5 + 125
= 8 + 80 + 125
= 213
( 10 mũ 3 + 10 mũ 4 + 125 mũ 2) : 5 mũ 3 = ( 1000 + 10000 + 15625) : 125
= 26625 : 125
= 213