![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
430 = 230 . 415 > 230 . 315 > 230 . 311 = 3 . 2410
\(\Rightarrow\)230 + 330 + 430 > 3 . 2410
Vậy 230 + 330 + 430 > 3 . 2410
![](https://rs.olm.vn/images/avt/0.png?1311)
2515=(52)15=530
810.330=(23)10.330=230.330=(2.3)30=630
vì 5<6 nên 530<630
hay 2515<810.330
25^15= ( 5^2)^15=5^30
8^10.3^30= (2^3)^10.3^30=2^30.3^30= (2.3)^30=6^30
tới đấy chắc biết làm rồi nhỉ
![](https://rs.olm.vn/images/avt/0.png?1311)
b) Ta có:
\(64^8=\left(8^2\right)^8=8^{16}=\left(2^3\right)^{16}=2^{48}\)
\(16^{12}=\left(2^4\right)^{12}=2^{48}\)
Vì \(2^{48}=2^{48}\) nên \(64^8=16^{12}\)
a) Ta có:
\(10^{20}=\left(2.5\right)^{20}=2^{20}.5^{20}\)
\(90^{10}=\left(2^2.3.5\right)^{10}=2^{20}.3^{10}.5^{10}\)
Vì \(2^{20}.5^{20}< 2^{20}.3^{10}.5^{10}\) nên \(10^{20}>90^{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{35^{10}.5^{10}}{49^5.125}=\frac{5^{10}.7^{10}.5^{10}}{\left(7^2\right)^5.5^3}=\frac{5^{20}.7^{10}}{7^{10}.5^3}=\frac{5^{17}.1}{1.1}=5^{17}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 1030 và 2100 .
1030 = ( 103 )10 = 100010 .
2100 = ( 210 )10 = 102410 .
Vì 100010 < 102410 .
\(\Rightarrow\) 1030 < 2100 .
Vậy ....
b) \(\uparrow\) Lm như trên .
![](https://rs.olm.vn/images/avt/0.png?1311)
chứng minh rằng A= 12/1*4*7+12/4*7*10+12/7*10*13+...+12/54*57*60<1/2
giải giup minh nha minh tich cho
![](https://rs.olm.vn/images/avt/0.png?1311)
////????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????không biết
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\Rightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)
\(\Rightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
Mà \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne=\)
\(\Rightarrow x+1=0\)
\(\Rightarrow x=0-1=-1\)
\(10^{30}>9^{30}\)
\(2^{100}< 2^{90}=\left(2^3\right)^{30}=8^{30}\)
\(9^{30}>8^{30}\)
\(\Rightarrow9^{30}>2^{100}\Rightarrow10^{30}>2^{100}\)
1030 < 2100