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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{3}{4}.\dfrac{2}{3}-\dfrac{1}{6}.\dfrac{3}{4}-\dfrac{3}{4}.\dfrac{1}{2}\)
= \(\dfrac{3}{4}.\left(\dfrac{2}{3}-\dfrac{1}{6}-\dfrac{1}{2}\right)\)
= \(\dfrac{3}{4}.0\)
= 0
\(\dfrac{3}{4}\cdot\dfrac{2}{3}-\dfrac{1}{6}\cdot\dfrac{3}{4}-\dfrac{3}{4}\cdot\dfrac{1}{2}\)
\(=\dfrac{3}{4}\left(\dfrac{2}{3}-\dfrac{1}{6}-\dfrac{1}{2}\right)\)
\(=\dfrac{3}{4}\cdot\left(\dfrac{4}{6}-\dfrac{1}{6}-\dfrac{3}{6}\right)\)
=0
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{3}x\)\(\frac{1}{2}-\frac{1}{5}x\)\(\frac{1}{2}\)
=(\(\frac{1}{3}-\frac{1}{5}\)) x \(\frac{1}{2}\)
=\(\frac{2}{15}x\)\(\frac{1}{2}\)
=\(\frac{1}{15}\)
1/3 * 1/2 - 1/5 * 1/2
= (1/3 + 1/5) * 1/2
=8/15*1/2
=4/15
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x:\dfrac{3}{4}=1-\dfrac{2}{5}\\ \Rightarrow x\cdot\dfrac{4}{3}=\dfrac{3}{5}\\ \Rightarrow x=\dfrac{3}{5}:\dfrac{4}{3}=\dfrac{9}{20}\)
\(x:\dfrac{3}{4}=1-\dfrac{2}{5}\)
\(\Rightarrow x:\dfrac{3}{4}=\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{3}{5}\times\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{9}{20}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có biểu thức :
\(M=\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)\)
a ) Nếu \(m=\frac{1}{2}\) thì \(M=\frac{11}{6}-\frac{5}{6}\div\left(\frac{1}{2}+\frac{3}{10}\right)=\frac{5}{4}\)
b ) Nếu \(M=\frac{5}{3}\) thì
\(\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(1\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(m+\frac{3}{10}=1\div\frac{5}{3}\)
\(m+\frac{3}{10}=\frac{3}{5}\)
\(m=\frac{3}{5}-\frac{3}{10}\)
\(m=\frac{3}{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1-\dfrac{2}{7}-\dfrac{1}{4}=\dfrac{7}{7}-\dfrac{2}{7}=\dfrac{1}{4}=\dfrac{5}{7}-\dfrac{1}{4}=\dfrac{20}{28}-\dfrac{7}{28}=\dfrac{13}{28}\)
=105/106
học tốt
105 phần 106