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Ta có: \(\left(0,125\right)^{x+1}=64\)
\(\Rightarrow\left(0,125\right)^{x+1}=\left(0,125\right)^{-2}\)
\(\Rightarrow\) \(x+1=-2\)
\(\Rightarrow\)\(x=-3\)
Vậy x = -3
\(0,125^{x+1}=64\\ 0,125^{-2}=64\Leftrightarrow x-1=-2\Leftrightarrow x=-1\)
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a)16. x2 = 64
x2 = 64 : 16
x2 = 4
x2 = 22
⇒ x = 2
b) (5.x - 2) - 64 = -36
(5.x - 2) = -36 + 64
5.x - 2 = 28
5.x = 28 + 2
5.x = 30
x = 30 : 5
x = 6
c) (2x - 10).(5 - x) = 0
TH1: 2x - 10 = 0
2x = 0 + 10
2x = 10
x = 10 : 2
x = 5
TH2: 5 - x = 0
x = 5 - 0
x = 5
⇒ Vậy x = 5.
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\(9^7.81:9^5=9^7.9^2:9^5=9^{7+2-5}=9^4\\ x^{12}:x.x^8=x^{12-1+8}=x^{19}\\ 16.2^4:8=2^4.2^4:2^3=2^{4+4-3}=2^5\\ 64.4^5:16=4^3.4^5:4^2=4^{3+5-2}=4^6\\ 3^{12}.3:3^8=3^{12+1-8}=3^5\\ 7^9.7^{12}:2015^0=7^{9+12}:1=7^{19}\)
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a) 4x = 64
Ta có 4 × 4 × 4 = 64
=> 43 = 64 => x = 3
Vậy x = 3
b) 2x = 16
Ta có 2 × 2 × 2 × 2 = 16
=> 44 = 64 => x = 4
Vậy x = 4
c) 9x - 1 = 9
9x = 9 + 1
9x = 10
=> Không có x thỏa mãn
Vậy, x \(=\varnothing\)
d) x4 = 16
Ta có 2 × 2 × 2 × 2 = 16
=> 24 = 16 => x = 4
Vậy x = 4
e) 2x ÷ 25 = 11
2x ÷ 32 = 11
2x = 11 × 32
2x = 352
Ta có 25 × 11 = 352
=> Không có giá trị nào thỏa mãn
Vậy, \(x=\varnothing\)
Cbht
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x^20-x=0
x(x^19-1)=0
x= 0
hoặc x ^ 19 =1
x = 0 hoặc x= 1
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\(\frac{5}{16}:0,125+1,456:\frac{7}{25}+\frac{9}{2}.0,8\)
\(=\frac{5}{16}:\frac{125}{1000}+\frac{1456}{1000}:\frac{7}{25}+\frac{9}{2}.\frac{8}{10}\)
\(=\frac{5}{16}.\frac{1000}{125}+\frac{1456}{1000}.\frac{25}{7}+\frac{18}{5}\)
\(=\frac{5}{2}+\frac{26}{5}+\frac{18}{5}\)
\(=\frac{25}{10}+\frac{52}{10}+\frac{36}{10}\)
\(=\frac{25+52+36}{10}=\frac{113}{10}\)
\(0,125^{x-2}\times16^{x-2}=64\)
\(0,125^{x-2}\times16^{x-2}=0,125^6\times16^6\)
\(\Rightarrow0,125^{x-2}=0,125^6\)
\(\Rightarrow x-2=6\)
\(\Rightarrow16^{x-2}=16^6\)
\(\Rightarrow x-2=6\)
\(x=6+2\)
\(x=8\)
Vậy \(x=8\)