Tìm x
3\x\=x+12
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a) x = 4
b) x = 3
c) x = 2
d) x = 1
e) x = 3
f) x = 2
g) x = 4
h) x = 3
\(\text{a)}f\left(x\right)-g\left(x\right)+h\left(x\right)=\left(x^3-2x^2+3x+1\right)-\left(x^3+x-1\right)+\left(2x^2-1\right)\)
\(=x^3-2x^2+3x+1-x^3-x+1+2x^2-1\)
\(=\left(x^3-x^3\right)+\left(-2x^2+2x^2\right)+\left(3x-x\right)+\left(1+1-1\right)\)
\(=2x+1\)
\(\text{b)Vì f(x)-g(x)+h(x)=0}\)
\(\Rightarrow2x+1=0\)
\(\Rightarrow2x\) \(=0-1=-1\)
\(\Rightarrow\) \(x\) \(=\left(-1\right):2=\dfrac{-1}{2}\)
\(\text{Vậy x=}\dfrac{-1}{2}\text{ thì f(x)-g(x)+h(x)=0}\)
a: \(f\left(x\right)-g\left(x\right)+h\left(x\right)\)
\(=2x^3-2x^2+4x+2x^2-1=2x^3+4x-1\)
b: f(x)-g(x)+h(x)=0
\(\Leftrightarrow2x^3+4x-1=0\)
\(\Leftrightarrow x\simeq0,2428\)
{[27x11-(x+12)x8]x3-79}:5=100
[27x11-(x+12)x8]x3-79=100x5=500
[27x11-(x+12)x8]x3=500+79=579
27x11-(x+12)x8=579:3=193
27x11-(x+12)=193:8=24,125
x+12=27x11-24,125
x+12=297-24,125
x+12=272,875
x=272,875-12
x=260,875.
Vay x=260,875.
{[27x11-(x+12)x8]x3-79}:5=100
[297 -(x+12)x8]x3-79 =100x5
[297 -(x+12)x8]x3-79 =500
[297 -(x+12)x8]x3 =500+79
[297 -(x+12)x8]x3 =579
297 -(x+12)x8 =579:3
297 -(x+12)x8 =193
(x+12)x8 =297-193
(x+12)x8 =104
x+12 =104:8
x+12 =13
x =13-12
x =1
Thử lại: {[27x11-(1+12)x8]x3-79}:5=100
\(\Leftrightarrow x^3=57\cdot14-12=786\)
hay \(x=\sqrt[3]{786}\)
\(\left(x^3+12\right):14=60+\left(-3\right)\\ x^3+12=798\\ x^3=786\\ x=\sqrt{786}\)
8 x 3 + 12 x 2 + 6x + 1 = 0
2 x 3 + 3. 2 x 2 .1 + 3.(2x). 1 2 + 1 3 = 0
2 x + 1 3 = 0
2x + 1 = 0
x = (-1)/2
\(1,A⋮B\Leftrightarrow x^3-3x^2-ax+3=\left(x-1\right)\cdot a\left(x\right)\)
Thay \(x=1\)
\(\Leftrightarrow1-3-a+3=0\\ \Leftrightarrow a=1\)
\(2,A⋮B\Leftrightarrow3x^3-16x^2+25x+a=\left(x^2-4x+3\right)\cdot b\left(x\right)\\ \Leftrightarrow3x^3-16x^2+25x+a=\left(x-3\right)\left(x-1\right)\cdot b\left(x\right)\)
Thay \(x=1\)
\(\Leftrightarrow3-16+25+a=0\\ \Leftrightarrow a=-12\)
Thay \(x=3\)
\(\Leftrightarrow3\cdot27-16\cdot9+25\cdot3+a=0\\ \Leftrightarrow81-144+75+a=0\\ \Leftrightarrow12+a=0\Leftrightarrow a=-12\)
Vậy \(a=-12\)
a)2x+17=35.
2x=35-17.
2x=18.
x=18:2.
x=9.
b)(x+12)*3=45.
x+12=445:3.
x=12=15.
x=15-12.
x=3.
Vậy........
a: P(x)=6x^3-4x^2+4x-2
Q(x)=-5x^3-10x^2+6x+11
M(x)=x^3-14x^2+10x+9
b: \(C\left(x\right)=7x^4-4x^3-6x+9+3x^4-7x^3-5x^2-9x+12\)
=10x^4-11x^3-5x^2-15x+21
giải nè: 3x-x =12 ( chuyển vế đổi dấu nhá)
2x = 12
x = 12: 2
x = 6
vậy x = 6 nah
chúc bạn hk tốt