Thực hiên phép tính sau bằng cách hợp lí
a. \(146+121+54+379\)
b. \(12.53+53.172-53.84\)
c. \(22344.36+44688.82\)
K
Khách
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Những câu hỏi liên quan
M
22 tháng 6 2019
1. Q=165+247+528+125+315
= 100+60+5+200+40+7+500+20+8+100+20+5+300+10+5
= ( 100+200+500+100+300) + ( 60+40+20+20+10 ) +( 5+7+8+5+5 )
= 1200+150+30
=1280
R=1234+5678+8+80
=1000+200+30+4+5000+600+70+8+8+80
= ( 1000+5000) + ( 200+600 ) + (30+70+80) + ( 4+8+8)
=6000+800+180+20
=7000
S
22 tháng 6 2019
Bài 1
Tính : Q=165+247+528+125+315
=(165+125)+(247+315+528)
=290+1090
= 1380
R=1234+5678+8+80
=(1234+6)+(5678+2)+80
= 1240+5680+80
= (1240+60)+(5680+20)
=1300+5700=7000
S
22 tháng 6 2019
Bài 2:
A= 243-97=(243+7)-(97-7)=250-90=160
B= 400-42-58=400-(42+58)=400-100=300
C=600-67-33=600-(67+33)=600-100=500
D=200-24-46=200-(24+46)=200-70=130
E=400-5-6-7-8=400-(5+6+7+8)=400-26=374
F= 764-115-268-43-32-20-85-37
=764-(115+85)-(268+32)-(43+37)-20
=764-200-300-80-20
=164
G=350-7-18-52-48-72
=350-(18+72)-(52+48)-7
=350-90-100-7
=160-7
=153
BN
1
9 tháng 11 2021
\(A=2019^2-\left(2019-3\right)\left(2019+3\right)\\ A=2019-2019^2-2019\cdot3+2019\cdot3+3^2\\ A=9\)
30 tháng 12 2021
a) (-124) + 24 = -100
b) 37. 78 + 37. 22
= 37 . ( 78 + 22 )
= 37 . 100
= 3700
29 tháng 10 2023
\(\dfrac{8}{9}+\dfrac{1}{3}=\dfrac{8}{9}+\dfrac{3}{9}=\dfrac{11}{9}\)
\(\dfrac{3}{4}-\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{2}{4}=\dfrac{1}{4}\)
\(\dfrac{7}{18}-\dfrac{1}{3}=\dfrac{7}{18}-\dfrac{6}{18}=\dfrac{1}{18}\)
\(\dfrac{2}{3}-\dfrac{7}{12}=\dfrac{8}{12}-\dfrac{7}{12}=\dfrac{1}{12}\)
\(\dfrac{4}{6}+\dfrac{1}{12}=\dfrac{2}{3}+\dfrac{1}{12}=\dfrac{8}{12}+\dfrac{1}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
\(\dfrac{19}{20}-\dfrac{3}{4}=\dfrac{19}{20}-\dfrac{15}{20}=\dfrac{4}{20}=\dfrac{1}{5}\)
\(\dfrac{9}{12}+\dfrac{3}{4}=\dfrac{3}{4}+\dfrac{3}{4}=\dfrac{6}{4}=\dfrac{3}{2}\)
\(\dfrac{1}{5}+\dfrac{2}{10}=\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{2}{5}\)
\(\dfrac{4}{5}-\dfrac{2}{15}=\dfrac{12}{15}-\dfrac{2}{15}=\dfrac{10}{15}=\dfrac{2}{3}\)
\(\dfrac{9}{18}+\dfrac{1}{2}=\dfrac{1}{2}+\dfrac{1}{2}=1\)
\(a,146+121+54+379\\ =\left(146+54\right)+\left(121+379\right)\\ =200+500\\ =700\)
\(b,12\cdot53+53\cdot172-53\cdot84\\ =53\cdot\left(12+172-84\right)\\ =53\cdot100\\ =5300\)
\(c,22344\cdot36+44688\cdot82\\ =44688\cdot18+44688\cdot82\\ =44688\cdot\left(18+82\right)\\ =44688\cdot100\\ =4468800\)