Question

[hà linh nguyễn thị hà linh]

Bài 1: 

a) 25%-(0,75+2\(\dfrac{1}{4}\))+2023⁰

b)\(\dfrac{31}{17}\)+\(\dfrac{-5}{13}\)+\(\dfrac{-8}{13}\)-\(\dfrac{14}{17}\)

c)\(\dfrac{-5}{7}\).\(\dfrac{-2}{11}\)+\(\dfrac{5}{7}\).\(\dfrac{-9}{11}\)+2024\(\dfrac{5}{7}\)

e) \(\dfrac{-5}{7}\).\(\dfrac{2}{11}\)+\(\dfrac{-5}{7}\).\(\dfrac{9}{11}\)+\(\dfrac{5}{7}\)

Bài 2: Tìm x:

a)\(\dfrac{2}{15}\)+2χ=\(-\dfrac{8}{45}\)

b) 5-(\(\dfrac{1}{3}\)χ+\(\dfrac{5}{6}\))=\(-\)0,5

c)\(\dfrac{-3}{4}\):\(\dfrac{-27}{12}\)-χ:\(\dfrac{2}{3}\)=\(\dfrac{-5}{6}\)

d) 0,4.(χ\(-\dfrac{3}{5}\))\(-\)\(\dfrac{2}{5}\)=0,16

e) \(\dfrac{2}{3}\)+\(\dfrac{1}{3}\):χ=\(\dfrac{-5}{6}\)

f) 0,25-\(\dfrac{3}{4}\):(χ-\(\dfrac{2}{3}\))=\(\dfrac{-5}{4}\)

Answer 1

[Nguyễn Thị Thương Hoài]

           Bài 1:

a; 25% - (0,75 + 2\(\dfrac{1}{4}\)) + 2023⁰

= 0,25 - (0,75 + 2,25) + 1

= 0,25 - 3 + 1

= 0,25 + (-3 + 1)

= 0,25  - 2

= - 1,75

b; \(\dfrac{31}{17}\) + \(\dfrac{-5}{13}\) + \(\dfrac{-8}{13}\) - \(\dfrac{14}{17}\)

= (\(\dfrac{31}{17}\) - \(\dfrac{14}{17}\)) - (\(\dfrac{5}{13}\) + \(\dfrac{8}{13}\))

= 1 - 1

= 0 

Answer 2

[Nguyễn Thị Thương Hoài]

Bài 1

c; \(\dfrac{-5}{7}\). \(\dfrac{-2}{11}\) + \(\dfrac{5}{7}\).\(\dfrac{-9}{11}\) + 2024\(\dfrac{5}{7}\)

= \(\dfrac{5}{7}\).(\(\dfrac{2}{11}\) - \(\dfrac{9}{11}\))  + \(\dfrac{14173}{7}\)

= - \(\dfrac{5}{11}\) + \(\dfrac{14173}{7}\)

=  \(\dfrac{155868}{77}\)