tìm x (x - 4) ^4 = 64
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4^x-5 + 4^x=64
4x : (4.4.4.4.4)+ 4x . 4=64
4x : ( 45+4)=64
4x : 46 = 64
4x : 4096=64
4x =64 . 4096= 262144
4x =49
Vậy x = 9
49 =262144
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\(\Rightarrow2^x+16=64\\ \Rightarrow2^x=48\Rightarrow x\in\varnothing\)
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`a,`\(2^x -15= 2^4+1\)
`-> 2^x-15=17`
`-> 2^x=17+15`
`-> 2^x=32`
`-> 2^x=2^5`
`-> x=5`
`b,` Có phải đề là \(\dfrac{x+1}{65}+\dfrac{x+2}{64}=\dfrac{x+3}{63}+\dfrac{x+4}{62}\) ?
`=>`\(\dfrac{x+1}{65}+1+\dfrac{x+2}{64}+1=\dfrac{x+3}{63}+1+\dfrac{x+4}{62}+1\)
`=>`\(\dfrac{x+1+65}{65}+\dfrac{x+2+64}{64}-\dfrac{x+3+63}{63}-\dfrac{x+4+62}{62}=0\)
`=>`\(\dfrac{x+66}{65}+\dfrac{x+66}{64}-\dfrac{x+66}{63}-\dfrac{x+66}{62}=0\)
`=>`\(\left(x+66\right)\left(\dfrac{1}{65}+\dfrac{1}{64}-\dfrac{1}{63}-\dfrac{1}{62}\right)=0\)
Mà `1/65+1/64-1/63-1/62 \ne 0`
`-> x+66=0`
`-> x=-66`
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a: =>2^x=2^4+16=32
=>x=5
b: Sửa đề: \(\dfrac{x+1}{65}+\dfrac{x+2}{64}=\dfrac{x+3}{63}+\dfrac{x+4}{62}\)
=>\(\left(\dfrac{x+1}{65}+1\right)+\left(\dfrac{x+2}{64}+1\right)=\left(\dfrac{x+3}{63}+1\right)+\left(\dfrac{x+4}{62}+1\right)\)
=>x+66=0
=>x=-66
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\(64.4^x=16^8\\ 4^3.4^x=\left(4^2\right)^8=4^{16}\\ 4^{3+x}=4^{16}\\ Nên:3+x=16\\ Nên:x=16-3\\ Vậy:x=13\)
`@` `\text {Ans}`
`\downarrow`
`(x - 4)^3 = 64?`
`=> (x - 4)^3 = 4^3`
`=> x - 4 = 4`
`=> x = 4 +4 `
`=> x = 8`
Vậy, `x = 8.`
hình như là mũ 4