19-(x-8)=12
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\(A=\frac{7}{19}.\frac{8}{11}.\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\left(\frac{7}{19}\right)^2.\frac{8}{11}.\frac{11}{3}+\frac{12}{19}\)
\(\Rightarrow A=\left(\frac{7}{19}\right)^2.\frac{8}{3}+\frac{12}{19}\)
\(\Rightarrow A=\frac{392}{1083}+\frac{12}{19}\)
\(\Rightarrow A=\frac{1076}{1083}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{56}{209}x\frac{7}{19}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{3971}:\frac{3}{11}+\frac{12}{19}\)
\(A=\frac{392}{1083}+\frac{12}{19}\)
\(A=\frac{1076}{1083}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) = 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
b) = 1/3 x 4/5 + 1/3 x6/5 + 1/3 x 2 = 1/3(4/5 + 6/5 + 2) = 1/3 x 4 = = 4/3
c) 4/7 x 2/9 + 4/7 x 7/9 + 2/3 = 4/7 x (2/9 + 7/9) + 2/3 = 4/7 x 1 + 2/3 = 26/21
A) 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
B) 1/3 x 4/5 + 1/3 x 6/5 + 1/3 x 2 = 1/3 x(4/5 + 6/5 x 2 ) = 1/3 x 4 = 4/3
c) TƯƠNG TỰ CÂU A VÀ B
* HOKTOT*
NHA
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1/ \(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
=\(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).0\)
=\(0\)
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( 10 + 12 + 13 + .... + 18 + 19 + 20 ) x ( 20 - 12 - 8 )
= ( 10 + 12 + 13 + .... + 18 + 19 + 20 ) x ( 8 - 8 )
= ( 10 + 12 + 13 + ... + 18 + 19 + 20 ) x 0
= 0
![](https://rs.olm.vn/images/avt/0.png?1311)
a: x-240:12=8
=>x-20=8
=>x=28
b: \(19+\dfrac{225}{6-x}=64\)
=>\(\dfrac{225}{6-x}=45\)
=>6-x=5
=>x=1
c: Đề thiếu rồi bạn
\(X-240:12=8\\ X-20=8\\ X=8+20=28\\ ---\\ 19+225:\left(6-X\right)=64\\ 225:\left(6-X\right)=64-19=45\\ 6-X=225:45=5\\ X=6-5=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: x+4/9=19/24
=>x=19/24-4/9=25/72
b: x-5/8=17/12
=>x=5/8+17/12=49/24
19-(x-8)=12
=>x-8=19-12
=>x-8=12
=>x=12+8
=>x=20
19-(x-8)=12
x-8=19-12
x-8=7
x=7+8
x=15