Cho: A = (100 × 6,8 + 100 × 3,2 ) × (3 741,48 : 100 + 2 242,52 : 100)
B = (16 × 14,96 × 2,5) × (0,1 × 27 + 0,1 × 73)
Tính A : B
Nhanh giúp mình
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\(A=\left(100\times44+50\times60\right)\times\left(37414,8:1000+2242,52:100\right)\)
\(A=\left(4400+3000\right)\times\left(3741,48\times\frac{1}{100}+2242,52\times\frac{1}{100}\right)\)
\(A=7400\times\left[\frac{1}{100}\times\left(3741,48+2242,52\right)\right]\)
\(A=7400\times\frac{1}{100}\times5984\)
\(A=74\times5984\)
\(B=\left(16\times14,96\times25\right)\times\left(27\times38+19\times146\right)\)
\(B=\left(4\times4\times25\times14,96\right)\times\left(27\times19\times2+19\times146\right)\)
\(B=\left(4\times100\times14,96\right)\times\left[19\times\left(54+146\right)\right]\)
\(B=4\times1496\times19\times200\)
\(B=5984\times19\times200\)
Ta có:
\(\frac{A}{B}=\frac{74\times5984}{5984\times19\times200}\)
\(\frac{A}{B}=\frac{37}{19\times100}\)
\(\frac{A}{B}=\frac{37}{1900}\)
Bài hơi dài, nếu có chỗ nào sai sót thì bạn thông cảm nhé
Cho \(A=\left(100\cdot44+50\cdot60\right)\cdot\left(\frac{37414,8}{1000}+2242,\frac{52}{100}\right)\)
\(B=\left(16\cdot14,96\cdot25\right)\cdot\left(27\cdot38+19\cdot146\right)\)
\(A=\left(100\cdot44+50\cdot2\cdot30\right)\cdot\left(3741,48\cdot\frac{1}{100}+2242,52\cdot\frac{1}{100}\right)\)
\(A=\left\{100.\left(44+30\right)\right\}.\left\{\left(3741,48+2242,52\right)\cdot\frac{1}{100}\right\}\)
\(A=7400\cdot5984\cdot\frac{1}{100}\)
\(A=74\cdot5984\)
\(B=\left(16\cdot14,96\cdot25\right)\cdot\left(27\cdot38+19\cdot146\right)\)
\(B=\left(4\cdot4\cdot14,96\cdot25\right)\cdot\left(27\cdot2\cdot19+19\cdot146\right)\)
\(B=100\cdot4\cdot14,96+\left\{19.\left(146+54\right)\right\}\)
\(B=1496\cdot4+19\cdot200\)
\(B=5984\cdot19\cdot200\)
=>\(\frac{A}{B}=\frac{5984\cdot74}{5984\cdot19\cdot200}\)
\(\frac{A}{B}=\frac{74}{19\cdot200}\)
\(\frac{A}{B}=\frac{37}{19\cdot100}\)( Vì giảm 200 : 2 = 100 . Lấy 74 :2 = 37 . Giảm 2 vế đi 2 lần )
=> A : B = 37/1900
Mình đã thử lại đúng nha bạn !
a. 7,3x2,5x0,8 b. 2,5x1,2x16
=7,3x(2,5x0,8) =(2,5x1,2)x16
=7,3x2 =3x16
=14,6 =48
a 27:0,1=270
27:10=2,7
b 134:0,1=1340
134:10 =13,4
c 768:0,01 768:100
a) 27:0.,1=270 27:10=2,7
b)134:0,1=1340 134:10=13,4
c)768:0,001=768000 768:100=7,68
a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{90}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{2}+\dfrac{1}{2}-...+\dfrac{1}{9}-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\dfrac{9}{10}\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=90-89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=1\)
\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}\)
\(\Rightarrow x=\dfrac{11}{25}\)
b) \(x\cdot9,85+x\cdot0,15=0,1\)
\(\Rightarrow x\cdot\left(9,85+0,15\right)=0,1\)
\(\Rightarrow x\cdot10=0,1\)
\(\Rightarrow x=\dfrac{0,1}{10}\)
\(\Rightarrow x=0,01\)
c) \(\dfrac{2}{5}+2022x=\dfrac{4}{10}\)
\(\Rightarrow\dfrac{2}{5}+2022x=\dfrac{2}{5}\)
\(\Rightarrow2022x=\dfrac{2}{5}-\dfrac{2}{5}\)
\(\Rightarrow2022x=0\)
\(\Rightarrow x=\dfrac{0}{2022}\)
\(\Rightarrow x=0\)
a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\left(1\right)\)
Ta có :
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
\(\left(1\right)\Rightarrow\dfrac{9}{10}.100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=89\)
\(\Rightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=90-89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)=\dfrac{1}{2}\)
\(\Rightarrow x+\dfrac{206}{100}=\dfrac{5}{2}:\dfrac{1}{2}\)
\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}.\dfrac{2}{1}\)
\(\Rightarrow x+\dfrac{103}{50}=5\)
\(\Rightarrow x=5-\dfrac{103}{50}\)
\(\Rightarrow x=\dfrac{250}{50}-\dfrac{103}{50}\)
\(\Rightarrow x=\dfrac{147}{50}\)
\(\text{a. 78,9 : 2,5 : 4. }\)
\(=31,56:4=7,89.\)
\(\text{ b. 56,75 + 8,4 : 4}.\)
\(=56,75+2,1=58,85.\)
\(\text{c. 23,6 x 100 + 2,9 : 0,1. }\)
\(=2360+29=2389.\)
\(\text{ d. 58 - 4,4 : 0,1}.\)
\(=58-44=14.\)