68:4+158-1025-(128:4)
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a) \(128-3\cdot\left(x+4\right)=23\)
\(\Leftrightarrow3\cdot\left(x+4\right)=105\)
\(\Leftrightarrow x+4=35\)
\(\Leftrightarrow x=31\)
b) \(\left(158-x\right):7=20\)
\(\Leftrightarrow158-x=140\)
\(\Leftrightarrow x=18\)
\(a,128-3.\left(x+4\right)=23\)
\(\Rightarrow3.\left(x+4\right)=128-23\)
\(\Rightarrow3.\left(x+4\right)=105\)
\(\Rightarrow\left(x+4\right)=105:3\)
\(\Rightarrow\left(x+4\right)=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
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Lời giải:
$128-[68+8(37-35)^2]:4=128-(68+8.2^2):4$
$=128-100:4=128-25=103$
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1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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128 - [68 + 8(37 - 35)2 ] : 4
= 128 - [68 + 8.22 ] : 4
= 128 - [68 + 32] : 4
= 128 - 100 : 4
= 128 - 25
= 103
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a, 1+2+3+4+....+2001+2002=(2002+1).[(2002-1)+1] :2
=2003.1001
= 2005003
-882